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koban [17]
3 years ago
10

A ________ allows users to add, remove, or edit its content.

Computers and Technology
2 answers:
Amanda [17]3 years ago
4 0
Wiki is the correct answer
ValentinkaMS [17]3 years ago
3 0

Answer:

In a wiki, the users can add or remove or edit their content.

Explanation:

wiki is a knowledge base website.

The wiki is a website where the users can together change the content.

In the normal wiki, the content is written in simple language and we can edit the text.

In the wiki, the users have the freedom to add, remove, or to edit their content.

Wiki is the content management system that means the users can modify the content as per their requirements.

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You are an IT administrator troubleshooting a Windows-based computer. After a while, you determine that you need to refresh the
Tanya [424]

Answer:

gpupdate

Explanation:

My explanation was previously removed.

6 0
2 years ago
When the tcp\ip translates a network layer address into a data link layer address (after not finding an entry for the network la
Pavel [41]
When the network stack translates an IP address (network address) to a MAC address (data link address) it sends a broadcast using ARP to all devices on the subnet asking who has the specified IP address.  The device with that IP address will then respond with it's MAC address to the ARP message's source.

With this in mind the answer to your question would either be broadcast or ARP request depending on what you have been learning in class.
6 0
3 years ago
Asking yourself questions can help you think of what to _____, in order to get answers.
Olenka [21]
Ask your self questions can help you think of what to measure, in order to get answers.
8 0
3 years ago
I need help with the stalk holders project
anygoal [31]

Answer:

A project is successful when it achieves its objectives and meets or exceeds the expectations of the stake­holders. But who are the stakeholders? Stakeholders are individuals who either care about or have a vested interest in your project. They are the people who are actively involved with the work of the project or have something to either gain or lose as a result of the project. When you manage a project to add lanes to a highway, motorists are stakeholders who are positively affected. However, you negatively affect residents who live near the highway during your project (with construction noise) and after your project with far-reaching implications (increased traffic noise and pollution).

Explanation:

6 0
3 years ago
g Write a program that prompts the user for an integer n between 1 and 100. If the number is outside the range, it prints an err
grin007 [14]

Answer:

The cpp program is given below.

#include<iostream>

#include<iomanip>

using namespace std;

int main() {

   

   // variables declared

   int n;

   int sum=0;

   float avg;

   

   do

   {

       // user input taken for number    

       cout<< "Enter a number between 1 and 100 (inclusive): ";

       cin>>n;

       

       if(n<1 || n>100)

           cout<<" Number is out of range. Enter valid number."<<endl;

       

   }while(n<1 || n>100);

   

   cout<<" "<<endl;

   

   // printing even numbers between num and 50  

   for(int num=1; num<=n; num++)

   {

       sum = sum + num;

   }

   

   avg = sum/n;

   

   // displaying sum and average

   cout<<"Sum of numbers between 1 and "<<n<<" is "<<sum<<endl;

   cout<<"Average of numbers between 1 and "<<n<<" is ";

   printf("%.2f", avg);

   

       return 0;

}

OUTPUT

Enter a number between 1 and 100 (inclusive): 123

Number is out of range. Enter valid number.

Enter a number between 1 and 100 (inclusive): 56

 

Sum of numbers between 1 and 56 is 1596

Average of numbers between 1 and 56 is 28.00

Explanation:

The program is explained below.

1. Two integer variables are declared to hold the number, n, and to hold the sum of numbers from 1 to n, sum. The variable sum is initialized to 0.

2. One float variable, avg, is declared to hold average of numbers from 1 to n.

3. User input is taken for n inside do-while loop. The loop executes till user enters value between 1 and 100. Otherwise, error message is printed.

4. The for loop executes over variable num, which runs from 1 to user-entered value of n.

5. Inside for loop, all the values of num are added to sum.

sum = sum + num;

6. Outside for loop, average is computed and stored in avg.

avg = sum/n;

7. The average is printed with two numbers after decimal using the following code.

printf("%.2f", avg);

8. The program ends with return statement.

9. All the code is written inside main() and no classes are involved.

3 0
3 years ago
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