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koban [17]
3 years ago
10

A ________ allows users to add, remove, or edit its content.

Computers and Technology
2 answers:
Amanda [17]3 years ago
4 0
Wiki is the correct answer
ValentinkaMS [17]3 years ago
3 0

Answer:

In a wiki, the users can add or remove or edit their content.

Explanation:

wiki is a knowledge base website.

The wiki is a website where the users can together change the content.

In the normal wiki, the content is written in simple language and we can edit the text.

In the wiki, the users have the freedom to add, remove, or to edit their content.

Wiki is the content management system that means the users can modify the content as per their requirements.

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Lemur [1.5K]
The Home ribbon contains the Paragraph attributes
7 0
3 years ago
Read 2 more answers
A small grocery store has one checkout.You have been asked to write a program to simulate the grocery store as it checks out cus
Masteriza [31]

Answer:

Check the explanation

Explanation:

PYTHON CODE :

#import random function

from random import randint

#class Queue declaration

class Queue:

#declare methods in the Queue

def __init__(self):

self. items = []

def isEmpty(self):

return self. items == []

def enqueue(self, item):

self.items. insert(0, item)

def dequeue(self):

return self. items. pop()

def size(self):

return len(self. items)

def getInnerList(self):

return self.items

#This is customer Queue

class Customer:

#declare methods

def __init__(self,n):

self.numberOfItems=n

def __str__(self):

return str(self. numberOfItems)

def getNumberOfItems(self):

return self. numberOfItems

#This is expresscheker customer queue

class Expresschecker:

def __init__(self,n):

self.numberOfItems=n

def __str__(self):

return str(self. numberOfItems)

def getNumberOfItems(self):

return self. numberOfItems

#Returns random checkout time, based on number of items

def checkOut(Expresschecker):

items = Expresschecker. getNumberOfItems()

if items <= 10:

return randint(2, 5)

if items <= 20:

return randint(6, 9)

return randint(10, 14)

#Initiate queue for the Expresschecker

Expresschecker = Queue()

#declare total customers

totalcheckoutCustomers = 10

#express Customers shopping..

for i in range(totalcheckoutCustomers):

#Each putting Between 1 to 25 items

randomItemsQty = randint(1, 25)

customer = Customer(randomItemsQty)

#Getting into queue for checkout

Expresschecker. enqueue(customer)

#====Now all express Customers having

#random qty of items are in Queue======

#intial time

totalTime=0

#define the size of the queue

totalcheckoutCustomers = Expresschecker. size()

#using for-loop until queue is empty check out

#the items in the express cheker queue

while not(Expresschecker. isEmpty()):

totalTime+=randint(1,5)

#Picking a customer

expresscustomer = Expresschecker. dequeue()

#Processing the customer

timeTaken = checkOut(expresscustomer)

#add the time for each custimer

totalTime+=timeTaken

#compute average waiting time

averageWaitingTime = totalTime/totalcheckoutCustomers

#display the average waiting time

print("Average waiting time for the express customer queue is "

+str(averageWaitingTime)+" minutes ")

print("Remaining Custimers in the express customer Queue is: ",

Expresschecker. size())

#Returns random checkout time, based on number of items

def checkOut(customer):

items = customer. getNumberOfItems()

if items <= 10:

return randint(1, 5)

if items <= 20:

return randint(6, 10)

return randint(11, 15)

#in

customersQueue = Queue()

totalCustomers = 20 #Change number of customers here

#Customers shopping..

for i in range(totalCustomers):

#Each putting Between 1 to 25 items

randomItemsQty = randint(1, 25)

customer = Customer(randomItemsQty)

#Getting into queue for checkout

customersQueue. enqueue(customer)

#====Now all Customers having random qty

#of items are in Queue======

totalTime=0

totalCustomers = customersQueue. size()

while not(customersQueue. isEmpty()):

totalTime+=randint(1,5)

#Picking a customer

customer = customersQueue. dequeue()

#Processing the customer

timeTaken = checkOut(customer)

totalTime+=timeTaken

#Result=============================

averageWaitTime = totalTime/totalCustomers

print("Average wait time for the customer queue is

"+str(averageWaitTime)+" minutes ")

print("Remaining Customers in the customer Queue is:

",customersQueue. size())

5 0
3 years ago
What would you have to know about the pivot columns in an augmented matrix in order to know that the linear system is consistent
Scrat [10]

Answer:

The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.

rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)

Then satisfying this theorem the system is consistent and has one single solution.

Explanation:

1) To answer that, you should have to know The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.

rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)

rank(A)

Then the system is consistent and has a unique solution.

<em>E.g.</em>

\left\{\begin{matrix}x-3y-2z=6 \\ 2x-4y-3z=8 \\ -3x+6y+8z=-5  \end{matrix}\right.

2) Writing it as Linear system

A=\begin{pmatrix}1 & -3 &-2 \\  2& -4 &-3 \\ -3 &6  &8 \end{pmatrix} B=\begin{pmatrix}6\\ 8\\ 5\end{pmatrix}

rank(A) =\left(\begin{matrix}7 & 0 & 0 \\0 & 7 & 0 \\0 & 0 & 7\end{matrix}\right)=3

3) The Rank (A) is 3 found through Gauss elimination

(A|B)=\begin{pmatrix}1 & -3 &-2  &6 \\  2& -4 &-3  &8 \\  -3&6  &8  &-5 \end{pmatrix}

rank(A|B)=\left(\begin{matrix}1 & -3 & -2 \\0 & 2 & 1 \\0 & 0 & \frac{7}{2}\end{matrix}\right)=3

4) The rank of (A|B) is also equal to 3, found through Gauss elimination:

So this linear system is consistent and has a unique solution.

8 0
3 years ago
Borrowing other images and videos are allowed as long as ________?​
My name is Ann [436]

Answer:

as long as there appropriate

6 0
2 years ago
____ is scientifically seeking and discovering facts.
galina1969 [7]

Answer:

I believe it is science, but before you do anything with this answer, research more on it, just in case I'm wrong! :)

Explanation:

3 0
2 years ago
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