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Mrac [35]
3 years ago
13

You are spreading fertilizer on a golf course at the rate of 40 pounds per 10000 square feet. If the course is 320 acres, how ma

ny tons of fertilizer will be needed?
Mathematics
1 answer:
Naddika [18.5K]3 years ago
7 0
<span>If you are spreading fertilizer on a golf course at the rate of 40 pounds per 10,000 square feet and the course is 320 acres, you can calculate the amount of fertilizer that will be needed by converting acres to square feet. So, 320 acres are 13,939,200 square feet which means you will need 55,756.8 pounds of fertilizer. </span>
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A Triangular Park ABC has sides 120 m, 80m and 50m. a gardener has to put a fence all around it and also plant grass inside. How
Vadim26 [7]

The perimeter = sum of all sides

= 120 + 80 + 50

= 250

So 250 - 3

247

Left space for gate

Now cost of fencing = Rs 20/per meter

= 247 × 20

= Rs 4,940

Now the area of the triangular park can be found using heron's formula

S = (a+b+c)/2

S = (120+80+50)/2

S = 250/2

S = 125

Now

Herons formula = √s(s-a)(s-b)(s-c)

√125(125-120)(125-80)(120-50)

√125(5)(45)(70)

√5×5×5×5×5×3×3×5×14

After Making pairs

5×5×5×3√14

375√14

Therefore 375√14m is the area of the triangular park

Must click thanks and mark brainliest

7 0
3 years ago
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Skill in adding and subtracting decimals is useful for calculating ______ .
Sholpan [36]

Answer:

<u>the amount saved in buying a pair of $32.95 blue jeans on sale for $26.50</u>

Step-by-step explanation:

all are pretty good answers but that one is most reasonable

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7 0
2 years ago
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Put in order the numbers from least to greatest |-12|, |11 3/4|, |-20.5|, |2|
ss7ja [257]

Answer:

|2|, |11 ¾|, |-12|, |-20.5|

Step-by-step explanation:

When you have absolute value, you basically remove the negative symbol.

3 0
2 years ago
It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp​
Semmy [17]

Answer:

\frac{1}{5}

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}, \frac{a^{m} }{a^{n} } = a^{(m-n)}, (a^m)^{n} = a^{mn}

Simplifying the product of the first 2 terms

\frac{a^{p^2+pq} }{a^{pq+q^2} } × \frac{a^{q^2+qr} }{a^{qr+r^2} }

= a^{p^2-q^2} × a^{q^2-r^2}

= a^{p^2-r^2}

Simplifying the third term

5((a^p+r)^{p-r}

= 5a^{(p+r)(p-r)} = 5a^{(p^2-r^2)}

Performing the division, that is

\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} } ← cancel a^{(p^2-r^2)} on numerator/ denominator leaves

= \frac{1}{5}

4 0
3 years ago
In a right triangular prism, the area of the triangular base is 50 square feet. The height of the prism is 12 feet. What is the
weeeeeb [17]

Answer: 600 ft.

Step-by-step explanation:

The height is 12, and the base is 50. So V=ABh=50·12=600ft³, just plug in the numbers.

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