All categories

3 years ago

Negative three plus x equals eleven

Mathematics

2 answers:

krek1111 [17]3 years ago

4 0

It would be 14 because since you have a -3 you would add that to 11 which would be 14

skad [1K]3 years ago

3 0

-3 + x = 11
x = 11 + 3
x = 14

You might be interested in

Heights for women are bell-shaped with a mean of 65 inches and standard deviation of 2.5 inches. If a random sample of 16 women

loris [4]

Answer:

μ= 65 inches; σ= 0.625 inch

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed(bell-shaped) random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\mu = 65, \sigma = 2.5$

By the central limit theorem, the sample of 16 will have:

$\mu = 65, \sigma = \frac{2.5}{\sqrt{16}} = 0.625$

So the correct answer is:

μ= 65 inches; σ= 0.625 inch

8 0

2 years ago

What does x equal ?<br> quick answer!!!

Anna35 [415]

136 should be your answer

4 0

3 years ago

How to find the average squared distance between the points of the unit disk and the point (1,1)

ddd [48]

The unit disk can be parameterized by the function

$\mathbf p(r,\theta)=(r\cos\theta,r\sin\theta)$

where $0\le r\le 1$ and $0\le\theta\le2\pi$ . The squared distance between any point in this region $(x,y)=(r\cos\theta,r\sin\theta)$ and the point (1, 1) is

$(x-1)^2+(y-1)^2=(r\cos\theta-1)^2+(r\sin\theta-1)^2$
$=(r^2\cos^2\theta-2r\cos\theta+1)+(r^2\sin^2\theta-2r\sin\theta+1)$
$=r^2(\cos^2\theta+\sin^2\theta)-2r(\cos\theta-\sin\theta)+2$
$=r^2-2r(\cos\theta-\sin\theta)+2$

The average squared distance is then going to be the ratio of [the sum of all squared distances between every point in the disk and the point (1, 1)] to [the area of the disk], i.e.

$\dfrac{\displaystyle\iint_{x^2+y^2$
$=\dfrac{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}[r^2-2r(\cos\theta-\sin\theta)+2]r\,\mathrm dr\,\mathrm d\theta}{\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}r\,\mathrm dr\,\mathrm d\theta}$
$=\dfrac{\frac{5\pi}2}\pi=\dfrac52$

5 0

3 years ago

Given the exact value for sides a and c.

Over [174]

Answer:

See below

Step-by-step explanation:

a = 15 sqrt 2 sin 45

= 15 sqrt 2 * sqrt( 2 ) /2 = 15 * 2 /2 = 15

sin 60 = a/c

sqrt(3)/2 = 15/c

c = 15 / ( sqrt(3)/2) = 30 / sqrt 3 = 30 sqrt 3 /3 = 10 sqrt 3

5 0

2 years ago

Can someone help me do this

DiKsa [7]

The answer is Angle T = angle N

8 0

2 years ago