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3 years ago

If y varies inversely as the square of x, and y= 1/8 when x=1, find y when x=5

Mathematics

2 answers:

Nata [24]3 years ago

5 0

y = k / x² ( y varies inversely as the square of x )

y = 1/8 when x = 1:

1/8 = k / 1²

8 k = 1

k = 1/8

For x = 5:

y = 1/8 / 5² = 1/8 : 25 = 1/8 · 1/25 = 1/200

Answer: A ) 1/200

Hope This Helps!!!

max2010maxim [7]3 years ago

4 0

Solution is given in image attached.

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A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard d

bagirrra123 [75]

The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C: [130.10, 143.90]

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How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

Sample size n > 30
Sample mean = $\overline{x}$
Sample standard deviation = s
Population standard deviation = $\sigma$
Level of significance = $\alpha$

Then the confidence interval is obtained as

Case 1: Population standard deviation is known

$\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}$

Case 2: Population standard deviation is unknown.

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For this case, we're given that:

Sample size n = 90 > 30
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Sample standard deviation = s = 34
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Thus, we get:

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Learn more about confidence interval for population mean from large samples here:

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