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Ghella [55]
3 years ago
7

I NEED HELP WORTH THIS there is one more option of 6,6 also

Mathematics
1 answer:
grigory [225]3 years ago
7 0

Answer:

C. (2,4)

Step-by-step explanation:

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Someone help me plzz
galina1969 [7]
Answer: y=5x+3
Step by step explanation:
Perpendicular meaning that the product of the slope/gradient is -1 hence ...
-1/5 * x = -1
x = -1/-1/5
x = 5
The equation perpendicular to y=-1/5x-3 is y=5x-c
Now it contains the points (1,2)
x variable is 1 and y variable is 2 plug them into the line equation
2=5(1)-c
2=5-c
2-5=-c
-3=-c divide by -1
3=c
Hence the perpendicular equation is y=5x+3
Hopefully it’s correct :)
5 0
3 years ago
Can someone please help me with this . will give brainliest :)​
Rasek [7]

Answer:

Your answer is going to be letter D because:

.00004 x 2,000,000,000 = 80,000

<u>D</u>

can i get brainly?

6 0
3 years ago
Quadrilateral ABCD ​ is inscribed in a circle.
Lerok [7]
In general, the sum of the measures of the interior angles of a quadrilateral is 360. This is true for every quadrilateral. This does not help here, because there are two angles (angles B and D) we know nothing about. We only know about opposite angles A and C.

In this case, you can use another theorem.
Opposite angles of an inscribed quadrilateral are supplementary.

m<A + m<C = 180

3x + 6 + x + 2 = 180

4x + 8 = 180

4x = 172

x = 43

m<A = 3x + 6 = 3(43) + 6 = 135

Answer: 135 deg
6 0
3 years ago
Which of the following are NOT factors of 24?
Pavel [41]

Answer:

5,7

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find the indicated arc and angle measures:
nevsk [136]

Answer:

arc AB = 70°

arc BC = 110°

arc ABC = 180°

arc CDB = 250°

Step-by-step explanation:

Since these angles are not inscribed, but are at the center point of the circle, the angles and arcs will be the same measure.

Solve for arc AB:

Angle AFB = 70°, so arc AB = 70°

Solve for arc BC:

Angle AFC is a straight angle so it is 180°. To find angle BFC, subtract angle AFB from 180°.

180 - 70 = 110°

Since angle BFC = 110°, arc BC = 110°

Solve for arc ABC:

Add arc AB and arc BC together.

70° + 110° = 180°

arc ABC = 180°

Solve for arc CDB:

There are 360° in a cirlce. To find arc CDB, subtract arc BC from 360°.

360° - 110° = 250°

arc CDB = 250°

7 0
3 years ago
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