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sergey [27]
3 years ago
5

1. En una comunidad del Cuzco la Lic. De Salud del Adulto Mayor (60 años a más) reportó los casos de diabetes de los seis primer

os meses del año 2019. Enero 24 ancianos Abril 18 ancianos Febrero 30 ancianos Mayo 28 ancianos Marzo 20 ancianos Junio 12 ancianos a) ¿A qué tipo de variable corresponden los datos? B) Elabora una Tabla de Frecuencias y determina la media, mediana y moda.
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
8 0

Answer:

The problem is about cases of diabetes in old people through months.

The variable is descrete , because it doesn't admit decimal numbers, it represents people, and people are whole numbers.

The frequency table would be

<h3> Months              People</h3>

January                       24

February                     30

March                          20

April                             18

May                             28

June                             12

The total number of people is 132.

The mean would be the total number of people divided by the six months.

\mu = \frac{132}{6} =22

Therefore, the mean is 22 people per month.

Remember that the median is the value at the center of the data set, which is between March and April, so

\frac{20+18}{2}=19

Therefore, the mean is 19.

The third statistical value is determined by the major frequency. So, the data that repeats the most is February, which means that month encloses the majority of people.

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Nancy found that x=1 is one solution to the quadratic equation (x 2)2=a. what is the value of a? -9 -3 3 9
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The value of the <em>a, </em>in the provided quadratic equation for which Nancy found one solution as x=1 is 9.

<h3>What is the solution of equation?</h3>

The solution of the quadratic equation is the solution of the variable of the equation, for which the equation satisfies.

Nancy found that x=1 is one solution to the quadratic equation. The quadratic equation is,

(x +2)^2=a

For this equation, one solution is <em>x</em>=1. Put this value in the above equation to get the value of <em>a,</em>

(1 +2)^2=a\\(3)^2=a\\9=a\\a=9

Thus, the value of the <em>a, </em>in the provided quadratic equation for which Nancy found one solution as x=1 is 9.

Learn more about the solution of the equation here;

brainly.com/question/21283540

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