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Leya [2.2K]
3 years ago
12

Please help! Will mark you Brinley!

Mathematics
1 answer:
Harman [31]3 years ago
4 0

Answer:

73627

Step-by-step explanation:

There:)

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Find all the real cube roots of 1000/27 <br><br><br> 10/3 <br> 10/9 <br> -10/9 <br> -10/3
gulaghasi [49]
Can you do prime factoriztion

1000
100 * 10
10 * 10 * 10

27
9 * 3
3 * 3 * 3

cube root (1000/27) = 10/3
7 0
2 years ago
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FIRST ONE TO ANSER WILL BE MARKED BRAINLIEST!!
FromTheMoon [43]
Ok so
-10, -6
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Two numbers are in the ratio 3:7
lbvjy [14]

Answer:

98 And 18 i think

Step-by-step explanation:

8 0
3 years ago
∠A and ∠B are vertical angles. If ∠A=8x+14 and ∠B=2x+50, what is m∠B?
Maslowich

Answer:

∠B = 62°

Step-by-step explanation:

Because ∠A and ∠B are vertical angles they are equal hence we can write

∠A = ∠B

8x + 14 = 2x + 50

Now we have to solve for x

To do so, subtract 2x on both sides of the equation:

6x + 14 = 50

Now, subtract 14 on both sides of the equation

6x = 36

Now, divide 6 on both sides of the equation

x = 6

To find m∠B you have to you have to plug in x = 6 back into the ∠B equation

∠B = 2(6) + 50

∠B = 62°

4 0
3 years ago
Simplify 7 square root of 3 end root minus 4 square root of 6 end root plus square root of 48 end root minus square root of 54
Katen [24]
7\sqrt3-4\sqrt6+\sqrt{48}-\sqrt{54}\\\\=7\sqrt3-4\sqrt6+\sqrt{16\cdot3}-\sqrt{9\cdot6}\\\\=7\sqrt3-4\sqrt6+\sqrt{16}\cdot\sqrt3-\sqrt9\cdot\sqrt6\\\\=7\sqrt3-4\sqrt6+4\sqrt3-3\sqrt6\\\\=\boxed{11\sqrt3-7\sqrt6}
3 0
3 years ago
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