The statement, "Julian's sister said he walked 1/5 mile" cannot be agreed because Julian totally walked
miles.
<u>Solution:</u>
Given that,
- Julian walked 6/10 of a mile to his friends house
- Another 35/100 mile to the store
- He walked 1/4 of a mile back home
To find total distance walked by Julian we have to add the above stated values. That is, 
Factors of 10 = 
Factors of 100 = 
Factors of 4 = 
Therefore, the least common factor of 10, 100 and 4 is 100. With like denominators we can operate on just the numerators,


Which can also be written as
.
So, from the above calculation it can be said that Julian walked
.
Answer:
The answer is the last one.
Step-by-step explanation:
When you do the others , they are step by step but when you do the last one, its just one step, which is -100.
Hope this helps :)
The mid-point of FJ is the number right in the middle of FJ. Find the mean of F & J. Add regardless of sign
4 + 6 = 10
10/2 = 5
Add 5 to -4
5 + -4 = 1
H is your midpoint
True. As long as AB and BC are on the same line, AB + BC = AC
hope this helps
Answer:
$3,623.84 Exact answer without rounding | $3,623.85 ~ (Approximent Answer with rounding.)
Step-by-step explanation:
Compound Interest Has a Specific Formula:
This case is Exponential Growth.
Formula: y= ab^x
You need to set up the equation.
First we need to define the rate of growth meaning what do you have to do for the 6.5%.
You need to do 100% + 6.5% = 106.5%
You need to convert the percent to a decimal which will be 1.065
Now we need to start plugging things into our formula to solve.
Your initial Starting amount was $3000
So you need to have y=3000(b)^x
We now know that the rate of growth is 1.065 so the b would be 1.065
y=3000(1.065)^x
Our power to x is our 3.5 years.
Our Equation now:
y=3000(1.065)^3
Now you need to use a calculator to do this due to the amount of decimals and digits.
Remember pemdas when doing this!!!
The answer should result to $3,623.84 but if rounded then: $3,623.85
Answer:
2.9375% Rounded or 2.94% not rounded
Step-by-step explanation: