Answer:Dimensions are of one corral is:
Length=50ft
Width= 37.5ft
Combined area=1875ft
Step-by-step explanation:
Let L= length
Let w = width
There are 3 pieces of fencing: 3L + 4w =300
W = (300 -3L)/ 4 ....equation 1
Combined area of the corrals is given by:
A= L × 2w...eq2
Put eq1 into eq2
A= L ×2(300-3L) /4
A= 1/2 (300 -3 L)^2
A= -(3/2)L^2 + 150
Using -b/2a to solve for L in the quadratic equation
-150/2(3/2) = (150×2)/(2×3)
L = 50ft
W= 300-3(50)/4
W=150/4=37.5ft
Combined are=50×37.5=1875ft
Answer:
.121
Step-by-step explanation:
Divide 121 by 1000
The excluded value is -16
C
Answer:
m1= 82
m2=98
m3=82
Step-by-step explanation:
Angle m4 is supplementary with angle m1 so their values add up to 180
180-98=82
Angle m3 is opposite of m1 and is the same value, it is also supplementary to m4 so you can find the value that way as well.
Angle m3 is opposite of m4 so it is the same value. It is supplementary to m1 and m3, so it must be 98 through that logic as well.