Jenny sleeps for 8 hours every day. How many days does she spend over the course
1 answer:
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First, let's find out the number of minutes Emily has to get to school. From 8:25 to 8:50, there are 25 minutes.
Next, let's find out the number of minutes before Emily looks at her watch. From 8:25 to 8:28.50, there are 3.5 minutes.
Now let's calculate Emily's speed in miles per minute. To do so, divide the distance traveled by the time it took:
miles/minute
Now let's calculate how far Emily can travel in 25 minutes going this speed. To do so, we multiply her speed by the time traveled:
miles
5.357 miles is greater than 3.42 miles, so yes, Emily will make it to school on time.
Next, let's find out the number of minutes before Emily looks at her watch. From 8:25 to 8:28.50, there are 3.5 minutes.
Now let's calculate Emily's speed in miles per minute. To do so, divide the distance traveled by the time it took:
Now let's calculate how far Emily can travel in 25 minutes going this speed. To do so, we multiply her speed by the time traveled:
5.357 miles is greater than 3.42 miles, so yes, Emily will make it to school on time.
Answer:
29% of the drive
Step-by-step explanation:
The plot of the problem is:
Transmitter at origin (0,0)
City to the north at (0,70)
City to the east at (74,0)
The path from city to city is a line with slope:
m = (-70)/74 = -35/37
and y-intercept at y = 70, so the equation is y = (-35/37)*x + 70.
The transmitter reach the area enclosed by the next circle:
x^2 + y^2 = 53^2
See the picture attached
The intersection is gotten from the picture or solving:
x^2 + [(-35/37)*x + 70]^2 = 53^2
the points approximately are: (24.1, 47.2) and (45.8, 26.7)
From Pythagorean theorem the total distance of the trip is:
d1 = √(70^2 + 74^2) ≈ 101.9 miles
And the distance when the signal is picked up is:
d2 =√ [(45.8 - 24.1)^2 + (47.2 - 26.7)^2] ≈ 29.9 miles
You will pick up a signal from the transmitter in (d2/d1)*100 = 29% of the drive.
