Question

After playing two football​ games, a professional football​ team's defense had given up an average of 28 points per game. After playing a third football​ game, the​ team's defense had given up an average of 22 points per game. How many points did the​ team's defense give up in the third football​ game? In the third football​ game, the​ team's defense gave up nothing points.

Answer 1

Answer:

In the third football game, the team's defense give up 10 points.

Explanation:

In two games, team has given up average of 28 points per game.

So, total points given up in two games is:

= (28 × 2)

= 56 points.

In three games, team has given up average of 22 points per game.

So, total points given up in three games is:

= (22 × 3)

= 66 points.

Points given up in third game:

= Total points given up in 3 games - Total points given up in 2 games

= 66 points - 56 points

= 10 points

So,

In the third football game, the team's defense give up 10 points.