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3 years ago

Use compatible number to find two estimates that the quotient is between 1,624 divided by 3

Mathematics

1 answer:

Alina [70]3 years ago

3 0

The correct answer is 541.2 to be exact

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The length of the sides of a triangle are 2x +y/2, 5x/3+y + ½ and 2/3x +2y +5/2. If the triangle is equilateral, find its perime

Sav [38]

Answer:

Step-by-step explanation:

If the triangle is equilateral :

2x +y/2 = 5x/3+y + ½ = 2/3x +2y +5/2

so the perimeter is : P = 3(2x +y/2) or 3(5x/3+y + ½) or 3(2/3x +2y +5/2)

the simplest is : P = 3(2x +y/2)

P = 6x + (3y)/2

6 0

3 years ago

Find Slope -5,3 and 7,8

34kurt

Answer:

5/12

Step-by-step explanation:

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3 years ago

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Reina added her business activity for the month of may in her notebook. She wants to find for profit for may?

Juliette [100K]

Answer:

6) What is Reina's profit for May?

write down how many dollars revenue (she acquired )

Month Business Activity Profit

April $13 $6 $7 show total = $26 revenue

May $9 $12 $3 = $24 revenue

Complete the sentence.

• A negative profit means that Reina spent ≥ ? ($)

on supplies than she earned in sales.

6 0

3 years ago

HELP ME MATH ASAP PLEASEE

bulgar [2K]

Answer:

What is the question??

7 0

3 years ago

The net weight in pounds of a packaged chemical herbicide is uniform for 49.62 < x < 50.04 pounds.

k0ka [10]

Answer:

a) $E(X)=\frac{50.64+49.62}{2}=50.13 pounds$

b) $Var(X)= \frac{(b-a)^2}{12} =\frac{(50.04-49.62)^2}{12}=0.0147$

c) $P(X$

But we see that the distribution is defined ust between 49.62 and 50.04

And in order to find this we can use the CDF (Cumulative distribution function) given by:

$F(X) =\frac{x-a}{b-a}$

And if we replace we got:

$P(X$

And makes sense since all the values are between 49.62 and 50.04

Step-by-step explanation:

For this case we define the random variable X ="net weigth in pounds of a packaged chemical herbicide" and the distribution for X is given by:

$X \sim U(a= 49.62, b=50.04)$

Part a

For the uniform distribution the expected value is given by $E(X) =\frac{a+b}{2}$ where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

$E(X)=\frac{50.64+49.62}{2}=50.13 pounds$

Part b

The variance for an uniform distribution is given by:

$Var(X)= \frac{(b-a)^2}{12}$

And if we replace we got:

$Var(X)= \frac{(b-a)^2}{12} =\frac{(50.04-49.62)^2}{12}=0.0147$

Part c

For this case we want to find this probability:

$P(X$

But we see that the distribution is defined ust between 49.62 and 50.04

And in order to find this we can use the CDF (Cumulative distribution function) given by:

$F(X) =\frac{x-a}{b-a}$

And if we replace we got:

$P(X$

And makes sense since all the values are between 49.62 and 50.04

6 0

4 years ago