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babymother [125]
4 years ago
10

Kylie and Ethan have each saved some money. I’m their savings, each coin is worth leas then 50 cents and each bill is less then

$10. Kylie has saved more money than Ethan, but he has more bills and coins than Kylie. She has one bill and seven coins. What is the amount of money each person could have?
Mathematics
1 answer:
timofeeve [1]4 years ago
7 0

Answer:

Kylie could have a $5 bill and seven quarters while Ethan could have two $1 bills and forty pennies.

Step-by-step explanation:

Since Kylie has seven quarters, that is seven multiplied by the value of the quarter, a quarter is 25 cents. So 7 x 25 = 125 OR $1 and 25 cents. Leaving Kylie with a total of $7 and 25 cents with the addition of the $5 bill.

Ethan has two $1 bills and forty pennies, forty multiplied by the value of the penny, a penny is 1 cent. So 40 x 1 = 40 OR 40 cents. Leaving Ethan with $2 and 40 cents with the addition of the two $1 bills from earlier.

Ethan has more bills and coins than Kylie and yet still has less money than Kylie.

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Help me with this problem please right away​
svlad2 [7]

Answer:

6\frac{1}{2} = A

Step-by-step explanation:

The first step is to use the Distance Formula to figure out the lengths of the two legs:

\sqrt{[-x_1 + x_2]^{2} + [-y_1 + y_2]^{2}} = D

R(1, 1) and P(−1, −2) ↷

\sqrt{[1 + 1]^{2} + [2 + 1]^{2}} = \sqrt{2^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13}\\ \\ \sqrt{13} = RP

Q(2, −4) and P(−1, −2) ↷

\sqrt{[1 + 2]^{2} + [2 - 4]^{2}} = \sqrt{[-2]^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13} \\ \\ \sqrt{13} = QP

* So, by my calculations, we have an isosceles <em>right triangle</em>, and according to the <em>45°-45°-90° triangle theorem</em>, we automatically know that the hypotenuse, <em>RQ</em>, is \sqrt{26}:

30°-60°-90° triangle theorem

2x, x, x√3

↑ ↑ ↑

h leg leg

y

p

o

t

e

n

u

s

e

45°-45°-90° triangle theorem

x√2, x, x

↑ ↑ ↑

h legs

y

p

o

t

e

n

u

s

e

So now, we have to find the area of the triangle by taking half of either height or base, then multiplying that by the height or base, but since this is an isosceles <em>right</em><em> </em><em>triangle</em><em>,</em><em> </em>it does not matter:

[\frac{h}{2}][b] = A \: \:OR\: \: [\frac{b}{2}][h] = A \: \:OR \: \: \frac{hb}{2} = A

[\frac{\sqrt{13}}{2}][\sqrt{13}] = \frac{13}{2} = 6\frac{1}{2} \\ \\ 6\frac{1}{2} = A

I am joyous to assist you anytime.

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