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Tresset [83]
3 years ago
11

12(13−14)−15=16+x+4 What is the value of x?

Mathematics
1 answer:
svlad2 [7]3 years ago
8 0
First, distribute the 12
156-168-15=16+4+x
-27=20+x
-47=x
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How can I factor -2x^2+2x+4=0 ?
Shtirlitz [24]
Because all are a multiple of 2, you can factor out 2, 2(-x^2+x+2)=0
4 0
3 years ago
Find an equation for the line perpendicular to 2x+ 6y = 30 and goes through the point (6,2)
Mashutka [201]

Answer:

y = 3x - 16

Step-by-step explanation:

We are asked to find the equation of the line perpendicular to 2x + 6y = 30

We can use two formulas for this question, either

y = mx + c. Or

y - y_1 = m(x - x_1)

Step 1: calculate the slope

From the equation given

2x + 6y = 30

Make y the subject of the formula

6y = 30 - 2x

Or

6y = -2x + 30

Divide both sides by 6, to get y

6y/6 = ( -2x + 30)/6

y = (-2x + 30)/6

Separate them in order to get the slope

y = -2x/6 + 30/6

y = -1x/3 + 5

y = -x/3 + 5

Slope = -1/3

Step 2:

Note: if two lines are perpendicular to the other, both are negative reciprocal of each other

Perpendicular slope = 3/1

Substitute the slope into the equation

y = mx + c

y = 3x + c

Step 3: substitute the point into the equation

( 6,2)

x = 6

y = 2

2 = 3(6) + c

2 = 18 + c

Make the c the subject

2 - 18 =c

c = 2 - 18

c = -16

Step 4: sub the value of c into the equation

y = 3x + c

y = 3x - 16

The equation of the line is

y = 3x - 16

If you try out the other formula, u will get the same answer

5 0
4 years ago
What x values would be good to use so she does not get fractions for her y values when making the table of ordered pairs.
Ber [7]

Answer:

-3, 0, 3

Step-by-step explanation:

Given, y = -\frac{4}{3}x + 2, the set of x values that will make Kayda not to get y values that are not fraction are -3, 0, 3.

This is so, because,

when x = -3, y = -\frac{4}{3}(-3) + 2 = \frac{12}{3} + 2 = 4 + 2 = 6

when x = 0, y = -\frac{4}{3}(0) + 2 = -0 + 2 = 2

when x = 3, y = -\frac{4}{3}(3) + 2 = \frac{-12}{3} + 2 = -4 + 2 = -2

The correct response is -3, 0, 3

5 0
3 years ago
Help please I’ll give brainliest
Sonja [21]
1/4 because there are 8 letters in vacation and two a’s meaning it’s a 2/8 chance simplify that to 1/4 (25%)
3 0
3 years ago
Read 2 more answers
Find (f −1)'(a).<br><br> f(x) = 4 + x2 + tan(πx/2), −1 &lt; x &lt; 1, a = 4
Vinvika [58]

Answer:

The  solution  is   (f^{-1})'(a) = \frac{2}{\pi }

Step-by-step explanation:

From the question we are told that

      The  function is  f(x) =  4 +  x^2  + tan [\frac{ \pi x}{2} ] ,     -1 <  x  <  1  a =  4

Here we are told find  (f^{-1}) (a)

Let equate

     f(x) =  a

So  

      4 +  x^2  + tan[\frac{\pi x }{2} ] =  4

       x^2  + tan[\frac{\pi x }{2} ]  =  0

For the equation above to be valid x must be equal to 0

  Now when x = 0

       f(0) = 4+0^2 + tan [\frac{ \pi * 0}{2} ]

=>      f(0) =  4

=>  0 =  f^{-1} (4)

Differentiating  f(x)

     f(x)'  =  0 + 2x  + sec^2 (\frac{\pi x}{2} )\cdot \frac{\pi}{2}

Now

    since 0 =  f^{-1} (4)

We have

      f(0)'  =  0 +  \frac{\pi }{2}  sec^2 (0)

       f(0)'  = \frac{\pi }{2}

Now  

        (f^{-1})'(a) =  \frac{1}{(\frac{\pi}{2} )}

        (f^{-1})'(a) = \frac{2}{\pi }

       

3 0
3 years ago
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