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Nastasia [14]
3 years ago
11

Based on the following graph, what is the most enjoyed candy and what is the approximate level of enjoyment?

Mathematics
2 answers:
MAXImum [283]3 years ago
4 0
Cotton candy 8.5 dont really get the level of enjoyment



sergiy2304 [10]3 years ago
3 0
Cotton candy and 8.2? I don't understand the level of enjoyment.
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7800$ increased by 6.5%
Nadusha1986 [10]
What is the question?

8 0
3 years ago
The fuel consumption rate of 10 vehicles is sampled. The rates, measured in miles per gallon, are 32, 24, 14, 34, 26, 27, 31, 16
blondinia [14]
The best estimate of the population mean is the sample mean

first calculate the sum of all samples:
32+24+14+34+26+27+31+16+18+26=248
then divide by the amount of samples to get the samples mean: 248/10=24.8 miles per gallon
8 0
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On Wednesday,Felipe drove 150 miles. This was 3 times the he distance he drove on Monday and 40 miles more than they drove on Tu
insens350 [35]
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8 0
3 years ago
Which is the equivalent expression in its most simplified form? <br><br> 5(2x – 3) + 7
N76 [4]
5(2x-3)+7
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10x-15+ 7
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10x-8
3 0
3 years ago
Given: Triangle ABC, mmBC=24 cm, line segment AL- &lt; bisector
Furkat [3]

The value of line AL is 21. 51cm

<h3>How to determine the length</h3>

To find line AL,

Using

Sin α = opposite/ hypotenuse to find line AB

Sin 90 = x/ 24

1 = x/24

Cross multiply

x = 24cm

Now, let's find line AC

Sin angle B = line AC/24

Note that to find angle B

angle A + angle B + angle C = 180

But angle B = 2 Angle A

x + 2x + 90 = 180

3x + 90 = 180

3x = 180-90

x = 30°

Angle B = 2 × 30 = 60°

Sin 60 = x/ 24

0. 8660 = x/24

Cross multiply

x = 24 × 0. 8660

x = 20. 78cm

We have the angle of A  in the given triangle to be divide into two by the bisector, angle A = 15°

To find line AL, we use

Cos = adjacent/ line AL

Cos 15 = 20. 78/ line AL

Line AL = 20. 78/ cos 15

Line AL = 20. 78 / 0. 9659

Line AL = 21. 51 cm

Thus, the value of line AL is 21. 51cm

Learn more about trigonometry ratio here:

brainly.com/question/24349828

#SPJ1

6 0
2 years ago
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