Step-by-step explanation:
1) Your problem → (4x^2 - 17x^3 + 9) - (x^2 + 9x + 23x^2 + 11)
(-17x^3+4x^2+9)-(x^2+23x^2+9x+11)
=-17x^3+4x^2+9-x^2-23x^2-9x-11
=-17x^3+4x^2-x^2-23x^2-9x+9-11
=-17x^3-20x^2-9x-2
2) Your problem → 0 - 19.73 - 25x^2 - 12x - 3
=0-19.73-25x2-12x-3
=-25x^2-12x-22.73
3) - 10.x^3 – 162x^2 – 24x - 4
4) Your problem → 17x^3 - 20x^2 - 9x^2
=17x^3-20x^2-9x^2
=17x^3-29x^2
5) -16x^3 – 243x^2 – 12x – 3
Step-by-step explanation:
A. part 1: $1.49 for 6 pencils
1 pencil would cost $1.49 / 6 = $0.24833(5s.f.) = $0.25 (nearest cent)
part 2: $4.60 for 20 pencils
1 pencil would cost $4.60 / 20 = $0.23
best value: part 2 (20pencil pack)
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Answer



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Answer:
b. 144.8
Step-by-step explanation:
When calculating the moving average estimate of an observation , each of the observations are usually computed with the same weighted . In some cases, it is beneficial to assign different weight on the observations such that the observation closer to the time period being forecast, has higher weight. This is refer to as weighted moving average technique. The sum of the individual weight in a weighted moving average technique must equal to 1.
The three-period weighted moving average forecast for period 5 = 144*0.5 + 148 *0.3 + 142 *0.2 = 144.8
Answer:
C
Step-by-step explanation:
cos(theta) is positive in IV quadrant and sin(theta)=sqrt(13^2-5^2)/13=-12/13