<h2>
Greetings!</h2>
Answer:
x = 67.5
Step-by-step explanation:
Because AB and NP lines are parrallel, we can find out the scale factor by dividing size MA by MN.
This works because you find out what the MA size has to be multiplied to to get to MN, which will also work in reverse to find angle MB from MP.
71.5 - 22 = MA = 49.5
71.5 ÷ 49.5 = 
So to get to line MP length, line MB had to be multiplied by
to get 97.5
The reverse of this is dividing 97.5 by
:
97.5 ÷
= 67.5
So x = 67.5
<h2>Hope this helps!</h2>
Triangle Area = .5 * base * height
Triangle Area = .5*15*12
Triangle Area = 90
Ok no me voy de vacaciones y no jnenener
This is a question of resolving the forces in question into horizontal and vertical and then finding the action of the resultant force.
The first force acts at an angle less than 90° and thus its resolved forces are positive. The second force acts at angle larger than 90° and is incident and thus its horizontal value is positive while its vertical value is negative.
Therefore;
For force of 300 N at 30°;
Horizontal value = 300*Cos 30 = 259.81 N
Vertical value = 300*Sin 30 = 150 N
For 150 N at 135°;
Horizontal value = 150*Cos (180-135) = 106.07 N
Vertical value = -150*Sin (180-135) = -106.07 N
Then,
Resultant horizontal value = 259.81+106.07 = 365.88 N
Resultant vertical value = 150-106.07 = 43.93 N
Therefore,
Resultant force, v = Sqrt (365.88^2+43.93^2) = 368.51 N
Angle of action measured from horizontal = tan ^-1(43.93/365.88) 6.85°
Then,
v = 368.51 N at 6.85° from horizontal
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Answer:
Molly
Step-by-step explanation:
Brady did not properly create a square.
The square of a binomial is ...
(a -b)² = a² -2ab +b²
Where a²=x² and -2ab = -4x, you find b=2. The constant term in the square is 2²=4. Brady shows it as -4, which is incorrect.
Molly's work is correct.