A solution with a pH of 11 has a [H+] of 
Option B is correct option.
Step-by-step explanation:
A solution with a pH of 11 has a [H+] of= ?
pH=?
Concentration of H+ [H+]= ?
Formula used: ![pH=-log[H+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%2B%5D)
Putting values and finding [H+]
![pH=-log[H+]\\\,[H+]\,=10^{-pH}\\\,[H+]\,=10^{-11}\\\,[H+]\,=1.0\times 10^{-11}](https://tex.z-dn.net/?f=pH%3D-log%5BH%2B%5D%5C%5C%5C%2C%5BH%2B%5D%5C%2C%3D10%5E%7B-pH%7D%5C%5C%5C%2C%5BH%2B%5D%5C%2C%3D10%5E%7B-11%7D%5C%5C%5C%2C%5BH%2B%5D%5C%2C%3D1.0%5Ctimes%2010%5E%7B-11%7D)
So, A solution with a pH of 11 has a [H+] of
Option B is correct option.
That is 6 * sqrt(2*8*3*6)
= 6 sqrt 16 * sqrt 18
= 6 *4 * sqrt 9 * sqrt2
= 6*4*3 sqrt2
= 72 sqrt 2
Answer:
the answer is. .6xy..........
Answer:
(4,1)
Step-by-step explanation:
let J(6,6) be x1, y1
let K(2,-4) be x2, y2
midpoint = (x1+x2)/2 , (y1+y2)/2
=(6+2)/2 ,(6-4)/2
= 8/2 ,2/2
=4, 1
Option C
For each value of y, -2 is a solution of -21 = 6y - 9
<u>Solution:</u>
Given, equation is – 21 = 6y – 9
We have to find that whether given set of options can satisfy the above equation or not
Now, let us check one by one option
<em><u>Option A) </u></em>
Given option is -5
Let us substitute -5 in given equation
- 21 = 6(-5) – 9
- 21 = -30 – 9
- 21 = - 39
L.H.S ≠ R.H.S ⇒ not a solution
<em><u>Option B)</u></em>
Given option is 3
- 21 = 6(3) – 9
- 21 = 18 – 9
- 21 = 9
L.H.S ≠ R.H.S ⇒ not a solution
<em><u>Option C)</u></em>
Given option is -2
- 21 = 6(-2) – 9
- 21 = - 12 – 9
- 21 = - 21
L.H.S = R.H.S ⇒ yes a solution
<em><u>Option D)</u></em>
- 21 = 6(9) – 9
- 21 = 54 – 9
- 21 = 45
L.H.S ≠ R.H.S ⇒ not a solution
Hence, the solution for the given equation is – 2, so option c is correct
