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3 years ago

How many roots does 2x^2-7x-5=0 have

Mathematics

1 answer:

Likurg_2 [28]3 years ago

7 0

$2x^2-7x-5=0$ has two roots: $x$ ≈ 4.10849528 and $x$ ≈ -0.60849528.

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A football team played 90 matches. They won 37 matches.

Mekhanik [1.2K]

Answer: 44 matches

Step-by-step explanation:

Let's take the given information

They won 37 matches

1/9th of their matches resulted in a draw

1/9 out of 90 is 9

You can take 90/9 and you will get 9

Now let us add 37+9 and you get 47

Now take 90-47

44 Matches lost

22/45 or 44/90

5 0

3 years ago

If f(x)=5x+1 and g(x)=2f(x)+5 then g(-1)=

ollegr [7]

We know f(x)=5x+1. Plug in f(x) in the g(x) function.
We get $g(x)=2(5x+1)+5$ Distribute the 2 to 5x and 1.
$g(x)=10x+2+5$
Simplify to get $g(x)=10x+7$
Now, we plug in -1 for x.
$g(-1)=10(-1)+7$
$g(-1)=-10+7$
$g(-1)=-3$

4 0

3 years ago

The ages of Lee's mother and aunt total 83 years. If her mothers age were doubled, then her mother would be 58 years older than

NemiM [27]

Answer:

sorry i dont know

Step-by-step explanation:

6 0

3 years ago

Name the types of angles shown.

PIT_PIT [208]

< ABC is a straight angle
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< ABD and < DBC are supplementary angles

7 0

3 years ago

Read 2 more answers

At 6:00 PM, a flagpole that is 35 feet tall casts a shadow that is 50 feet long. At the same time, how long will a person's shad

sertanlavr [38]

Answer:

The length of the person’s shadow is 5.7ft

Explanation:

Length of the flagpole =a= 35ft

Length of the shadow of the flagpole= b=50ft

Length of the person=c= 4ft

Suppose the length of the person’s shadow is=d

According to the rules of trigonometry

$\frac{\text { Length of the flagpole }}{\text { Length of the shadow of the flagpole }}=\frac{\text { Length of the person }}{\text { Length of the person's shadow }}$

$\frac{a}{b}=\frac{c}{d}$

$\frac{35}{50}=\frac{4}{d}$

35d=200

d= $\frac{200}{35}$

d=5.7ft

Hence, The length of the person’s shadow is 5.7ft.

3 0

3 years ago