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Zinaida [17]
2 years ago
11

The midpoint of segment AB is M(26, -111). The coordinates of one endpoint is

Mathematics
2 answers:
hammer [34]2 years ago
7 0

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
A(\stackrel{x_1}{31}~,~\stackrel{y_1}{25})\qquad
B(\stackrel{x_2}{x}~,~\stackrel{y_2}{y})
\qquad
\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{x+31}{2}~~,~~\cfrac{y+25}{2} \right)=\stackrel{\stackrel{midpoint}{M}}{(26,-111)}\implies \begin{cases}
\cfrac{x+31}{2}=26\\[0.8em]
x+31=52\\
\boxed{x=21}\\[-0.5em]
\hrulefill\\
\cfrac{y+25}{2}=-111\\[0.8em]
y+25=-222\\
\boxed{y=-197}
\end{cases}

butalik [34]2 years ago
4 0
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Answer:

A

Step-by-step explanation:

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3 years ago
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ser-zykov [4K]

Answer:

\boxed{\sf k=6}

Step-by-step explanation:

\sf kx (x-2)+6=0

Expand brackets.

\sf kx^2 -2kx+6=0

This is in quadratic form.

\sf ax^2 +bx+c=0

Since this is for equal roots:

\sf b^2 -4ac=0

\sf a=k\\b=-2k\\c=6

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Plug k as 0 to check.

\sf \sf 0x^2 -2(0)x+6=0\\6=0

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3 years ago
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