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Elodia [21]
4 years ago
15

If a cylindrical tank holds 100,00 gallons of water which can be drained from thebottom of the tank in an hour, then Torricelli’

s Law gives the volumeVof waterremaining in the tank aftertminutes asV(t) = 100,000(1−160t)20≤t≤60(a) What is the physical meaning ofV′(t)? What are the units?(b) Find and interpret the quantityV′(10).
Mathematics
1 answer:
tatyana61 [14]4 years ago
5 0

Answer:

First, I think the right formula is:

V(t) = 100,000(1-\frac{t}{60} ),20\leq t\leq 60

A) We first derive the formula given above:

V'(t)=-\frac{100000}{60}

V'(t) represent the drain rate of the tank volume.

B) the units is: gallons/time

C) at V'(10) = 100000/60 = 1666.66 gallons/time.

because the formula V'(t) is constant so it doesn't depend of time.

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The answer to your question is c
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3 years ago
43/14 as decimal rounded to nearest hundredth
anzhelika [568]

Answer:The answer would be 3.07.


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Hope this helps!



5 0
3 years ago
Read 2 more answers
Would appreciate the help ! ​
aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 2

\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 3

\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity \sin^2(\theta)+\cos^2(\theta) = 1 in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0
3 years ago
I need help ASAP. Will give Brainliest.
Volgvan

Answer:

4,5

Step-by-step explanation:

Your welcome! :)

Good Luck!

8 0
3 years ago
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Show me how to change this decimal to a fraction.
galben [10]

Answer:

98/99

Step-by-step explanation:

0.98 (both the 9 and 8 repeat)

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5 0
3 years ago
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