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<h3>Final value : x² -9x - 11</h3>
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<h3>Step by step </h3>
2x + 1 = ⅕ × (x² + x - 6)
2x + 1 = ⅕x² + ⅕x - 6/5
1/5x² +1/5x - 2x - 6/5 - 1 = 0
1/5x² -9/5x - 11/5 = 0
x² - 9x - 11 = 0. #times by 5
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#Give me brainliest pls im tired typing all of this
Slope of 2y = x + 5:-
This is y = 0.5 x + 2.5 in slope intercept form so its slope = 0.5
Slope of the line perpendicular to it = -1 / 0.5 = -2
it passes through (2 , 1) so we have
y- 1 = -2(x - 2)
y = -2x + 4 + 1
The answer is y = -2x + 5
Hello There!
-What We Know-
Erin made 66 deviled eggs for a party.
After an hour 8 eggs were left.
X amount of eggs were eaten within the first hour.
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We subtract 8 eggs how many were left after the hour
From how many eggs we had in total.
66-8=58.
58 eggs were eaten within the hour.
IQR = 40
1) Put the numbers in order: 40, 45, 50, 60, 60, 75, 90, 90, 120
2) Find the median: Median is 60 (the 2nd one)
3) Place parentheses around the numbers above and below the median. For easy identification of Q1 and Q3. (40, 45, 50, 60,) 60, (75, 90, 90, 120)
4) Find the Q1 and Q3. Q1 = median of the lower half of the data; Q3 = median of the higher half of the data. Q1 and Q3 have even sets so its median cannot be defined.
5) Had both sets contain odd sets, the median of Q1 is subtracted from the median of Q3 to get the IQR.
We can then use the Alternative definition of IQR.
IQR is the difference between the largest and smallest values in the middle 50% of a set data.
40, 45, 50, 60, 60, 75, 90, 90, 120
Middle 50% is 50, 60, 60, 75, 90; IQR = Largest value - smallest value;
IQR = 90 - 50 = 40
