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3 years ago

2,000 is 10 times as much as

Mathematics

2 answers:

Kamila [148]3 years ago

4 0

2000 ÷ 10 = 200

200 × 10 = 2000

castortr0y [4]3 years ago

4 0

2,000 is 10 times as much as 200 because 2,000 has one more 0 which is 10 of a spot

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3 years ago

A pet store sells dog food in a 3-pound bag for $12.00 and a 5-pound bag for $14.25. Which bag of dog food is the better buy? Ex

Bess [88]

The 5-pound bag is better value.

The easiest way to compare and find out which is a better buy is to find out how much is being charged for 1-pound of food in each bag.

$12 is divided by 3 beacuse it's a 3-pound bag and we are aiming to find what 1-pound is equal to.

$12 ÷ 3 = $4

So the first bag charges $4 per pound of food.

Then use the same method for the 5-pound bag.

$14.25 ÷ 5 = $2.85

So the second charges $2.85 per pound of food.

So as we can see, the 5-pound bag is clearly better value. For each pound of food you are saving $1.15 in comparison to what you would be spending if you opted for the first bag.

Hope this helps!

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3 years ago

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neonofarm [45]

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3 years ago

Drawing a red marble from a bag of six red and 4 blue replacing it and then drawing a blue marble

Ksivusya [100]

Answer:

The probability of picking a red marble and a blue marble = 6/25

Step-by-step explanation:

Here, the question is INCOMPLETE.

What is the probability of this independent event. Drawing a red marble from a bag of 6 red and 4 blue marbles, replacing it, and then drawing a blue marble.

Here, total number of red marble in bag = 6

total number of blue marble in bag = 4

So, total marbles in the bag = 6 + 4 = 10 marbles

Now,if E : Any given event, then

$\textrm{P (Event E)} = \frac{\textrm{Total number of favorable outcomes}}{\textrm{Total Outcomes}}$

So, here $\textrm{P (Picking a Red marble)} = \frac{\textrm{Total number of red marble}}{\textrm{Total marble}} = \frac{6}{10} = \frac{3}{5}$

⇒ P(a Red ball) = 3/5 ...... (1)

Now, if the picked marble is REPLACED, then total marbles in the bag = 10

So, here $\textrm{P (a Blue marble)} = \frac{\textrm{Total number of blue marble}}{\textrm{Total marble}} = \frac{4}{10} = \frac{2}{5}$

⇒ P(a Blue marble) = 2/5 ...... (2)

So, the probability of picking a red marble and a blue marble AFTER REPLACING

=P(a Red marble) x P(a Blue marble) = 3/5 x 2/5 = 6 /25

Hence, the probability of picking a red marble and a blue marble = 6/25

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4 years ago