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Crazy boy [7]
3 years ago
12

I don't understand how to graph or how to find domain and range

Mathematics
2 answers:
kenny6666 [7]3 years ago
6 0
Domain- from left to right.: Range- from top to bottom.


Lynna [10]3 years ago
5 0
Just mark the coordinates on the x- & y-axis and draw the line, in order to graph an equation.

Domain = x-coordinates of graph  [ Horizontal line ]
Range = y - coordinated pf graph  [ Vertical line ]

Hope this helps!
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What is the area of cross-section ADGF of this right rectangular prism?
dedylja [7]

Answer:

C.52 square units

Step-by-step explanation:

We are given that

Length of cross-section ADGF,l=13units

Length of cross-section ADGF, b=4 units

We have to find the area  of cross-section ADGF of this right rectangular prism.

We know that

Area of rectangle=l\times b

Using the formula

Area of cross-section ADGF of this right rectangular prism

=13\times 4

Area of cross-section ADGF of this right rectangular prism=52square units

Option C is correct.

C.52 square units

5 0
2 years ago
A line passes through the points (11, -5) and (-11, -7). What is its
ira [324]

Explanation is in the file

tinyurl.com/wpazsebu

5 0
3 years ago
I need help with this
KiRa [710]

Answer:

A: 56= 5y - 19

b: 68

Step-by-step explanation:

Since it is an isosceles triangle because two sides are congruent, the corresponding angles are also congruent.

3 0
3 years ago
A restaurant uses 3 pounds of pasta for a party of 14 people. If they are cooking pasta for a party of 56 people, what should th
azamat
If you would like to know how many pounds of pasta the restaurant will need, you can calculate this using the following steps:

3 pounds of pasta ... 14 people
x pounds of pasta = ? ... 56 people

3 * 56 = 14 * x      /14
x = 3 * 56 / 14
x = 12 pounds of pasta

The correct result would be 12 pounds of pasta.
3 0
3 years ago
Read 2 more answers
The zeros of a function are the values of x x for which the function is equal to zero. Enter a number in each blank to make true
Anit [1.1K]

Answer:

1 or 5

Step-by-step explanation:

Given the function h(x)=(2x−2)(x−5)

The zeros of h(x) are the values of x for which h(x)=0

h(x)=(2x−2)(x−5)=0

Note that if a.b=0, either a=0 or b=0.

Appying the above,

If (2x−2)(x−5)=0

Then:

2x−2=0 or x-5=0

2x=2 or x=5

x=1 0r 5

The zeroes of h(x) as defined are 1 or 5.

8 0
3 years ago
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