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3 years ago

14

21 students in michael's classroom are wearing jeans. there are 25 students in his class.michael says that 80% of his class is w

earing jeans.is michael correct ? explain your reasoning.

2 answers:

jek_recluse [69]3 years ago

5 0

No, Michael would not be correct. 84% of his class would be wearing jeans. I divided 21 by 25, which came out to be .84.

grigory [225]3 years ago

3 0

There are a total of 25 students in Michael's classroom. Given 21 students are wearing jeans.

Michael said that 80% of his class is wearing jeans.

So we can get the number of students wearing jeans by finding 80% of 25 students.

80% of 25 = 25 × 80/100 = 2000/100 = 20

So 80% of 25 students is 20 students.

But given 21 students are wearing jeans.

So, Michael is not correct as 21 students are not 80% of his classroom.

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.Adam is 3 times as old as his sister Naya , in 4 years he will be twice as old as Naya , how old are Adam and Naya now ?

galben [10]

Step-by-step explanation:

The answer is

If naya is 4 years old then 3 times Adam age is 12

After 4 years naya is 8 years old and Adam is 16

We can check it because twice of 8 is 16

So now Adam is 12 years and Naya is 4 years old

5 0

3 years ago

Bob and Anna are planning to meet for lunch at Sally's Restaurant, but they forgot to schedule a time. Bob and Anna are each goi

Viktor [21]

Answer:

The expected cost is $8.75

<em></em>

Step-by-step explanation:

Given

$Time = \{1pm, 2pm, 3pm, 4pm\}$

$C_1 = \$5$ --- If Bob and Anna meet

$C_2 = \$10$ --- If Bob and Anna do not meet

Required

The expected cost of Bob's meal

First, we list out all possible time both Bob and Anna can select

We have:

$(Bob,Anna) = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3)$ $,(3,4),(4,1),(4,2),(4,3),(4,4)\}$

$n(Bob, Anna) = 16$

The outcome of them meeting at the same time is:

$Same\ Time = \{(1,1),(2,2),(3,3),(4,4)\}$

$n(Same\ Time) = 4$

The probability of them meeting at the same time is:

$Pr(Same\ Time) = \frac{n(Same\ Time)}{n(Bob,Anna)}$

$Pr(Same\ Time) = \frac{4}{16}$

$Pr(Same\ Time) = \frac{1}{4}$

The outcome of them not meeting:

$Different = \(Bob,Anna) = \{(1,2),(1,3),(1,4),(2,1),(2,3),(2,4),(3,1),(3,2)$

$,(3,4),(4,1),(4,2),(4,3)\}$

$n(Different) = 12$

The probability of them meeting at the same time is:

$Pr(Different) = \frac{n(Different)}{n(Bob,Anna)}$

$Pr(Different) = \frac{12}{16}$

$Pr(Different) = \frac{3}{4}$

The expected cost is then calculated as:

$Expected = C_1 * P(Same) + C_2 * P(Different)$

$Expected = \$5 * \frac{1}{4} + \$10 * \frac{3}{4}$

$Expected = \frac{\$5}{4} + \frac{\$30}{4}$

Take LCM

$Expected = \frac{\$5+\$30}{4}$

$Expected = \frac{\$35}{4}$

$Expected = \$8.75$

<em>The expected cost is $8.75</em>

4 0

2 years ago

I invited 8 people to a party (including me) and i only had 3 brownies. How much did each person get if everyone got a fair shar

Masja [62]

Answer:

0.375

Step-by-step explanation:

Just divide 3 over 8.

5 0

3 years ago

Read 2 more answers

4. The diagram at right shows the graph of 3x + 4y = 12. The shaded figure is a square, three of whose vertices are on the coord

nikklg [1K]

Remark

This is a very interesting question. Draw a line from the origin to where the upper right vertex of the square touches the line. That line has the property that the its equation is y = x. So the "solution" to the point of intersection is the solution of the two equations.

y = x (1)

3x + 4y = 12 (2)

Put x in for y in equation 2

3x + 4x = 12

7x = 12

x = 12/7

x = 1.714

y = 1.714

Problem A

<em><u>x intercept</u></em>

The x intercept occurs when y = 0

3x + 4(0) = 12

3x = 12 Divide by 3

x = 12/3

x = 4

the x intercept = (4,0)

<em><u>y intercept</u></em>

The y intercept occurs when x =0

3(0) + 4y = 12

4y = 12

y = 12/4

y = 3

y intercept = (0,3)

Problem B

x and y both equal 1.714 so they are also the length of the square's side.

Problem C

See solution above. x =y is the key fact.

x = y = 1.714

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3 years ago

Which polynomial is a difference of two squares? x2 − 16 x2 + 16 x2 − 8 x2 + 8

mart [117]

Difference means subtract so we can reduce the choices right away to first and third choices. of the only the first is the difference of squares, namely x² - 4²

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3 years ago