Answer:
Brainleist!
Step-by-step explanation:
V = (36 x 11) / 3
V = 396/3
V = 132 in^3
The dimensions of the rectangular base of the building with the given perimeter are 120ft and 285ft.
<h3>What are the dimensions of the rectangle base?</h3>
The perimeter of rectangle is expressed as;
P = 2( l + w )
Given the data in the question;
Let x represent the width of the rectangular base.
- Width w = x
- Length = l = 3x-75
- Perimeter P = 810ft
Plug these values into the equation above.
P = 2( l + w )
810 = 2( (3x-75) + x )
810 = 6x - 150 + 2x
810 = 8x - 150
8x = 810 + 150
8x = 960
x = 960/8
x = 120
Hence,
Width of the rectangle = x = 120ft
Length of the rectangle = 3x-75 = 3(120) - 75 = 285ft
Therefore, the dimensions of the rectangular base of the building with the given perimeter are 120ft and 285ft.
Learn more about rectangles here: brainly.com/question/17043956
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Answer:
- (a-2)(3a-5)
- (b-3)(5b-17)
Step-by-step explanation:
Recognize that b-a = -(a-b). (Reversing the order of a difference changes its sign.)
1. 3(a-2)² -(2-a) = 3(a-2)² +(a-2) = (a-2)(3(a-2) +1)
... = (a -2)(3a -5)
2. 2(3-b) +5(b-3)² = (b -3)(-2 +5(b -3))
... = (b -3)(5b -17)
125 = 5 * 5 * 5 = 5³
90 = 2 * 3 * 3 * 5 = 2 * 3² * 5
92 = 2 * 2 * 23 = 2² * 23
