Answer:
y = 2x² - 10
Step-by-step explanation:
We must find a pattern in the numbers. Set out the numbers in a table (Columns 1 and 2 in the table).
<u>x</u> <u> y</u> <u>y/2</u> <u>y/2 + 5
</u>
2 -2 -1 4
3 8 4 9
4 22 11 16
5 40 20 25
It looks like all y-values are multiples of 2.
Let's divide them by 2 (Column 3).
The numbers don't increase evenly. We may have a quadratic function.
If we add 5 to each quotient, we get a set of values equal to x² (Column 4).
y/2 + 5 = x²
y + 10 = 2x²
y = 2x² - 10
The function is y = 2x² - 10.
Answer:
1. x=3 x=1
2. x=0
Step-by-step explanation:
We want f(x) to equal g(x)
f(x)=g(x)
1/(x-2) = (x-2)
Using cross products
1 = (x-2) * (x-2)
1 = x^2 -2x-2x+4
Subtract 1 from each side
1-1 = ^2 -2x-2x+4-1
0 = x^2 -4x+3
Factoring
What number multiplies to 3 and adds to -4
-3*-1 = 3
-3+-1 = -4
0= (x-3) (x-1)
Using the zero product property
x-3 =0 x-1=0
x=3 x=1
2. f(x)=x^2+4x+2
g(x)=(1/2)^ x+1
From the graph,we can see they intersect at x=0
Answer:
Option b is the correct answer
Step-by-step explanation:
Answer:
what
Step-by-step explanation:
Answer:
x = 21
Step-by-step explanation:
To see for what value of x is the equation true, we have to solve x.
![\displaystyle \frac{2}{3} x - 3 = 11\\\\Adding \ 3 \ to \ both \ sides\\\\\frac{2x}{3} = 11 + 3\\\\\frac{2x}{3} = 14\\\\Multiply \ 3 \ to \ both \ sides\\\\2x = 14 \times 3\\\\2x = 42 \\\\Divide\ both\ sides\ by\ 2\\\\x = 42/2\\\\x = 21\\\\For \ x = 21\ the \ given \ equation \ is \ true.\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B2%7D%7B3%7D%20x%20-%203%20%3D%2011%5C%5C%5C%5CAdding%20%5C%203%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C%5Cfrac%7B2x%7D%7B3%7D%20%3D%2011%20%2B%203%5C%5C%5C%5C%5Cfrac%7B2x%7D%7B3%7D%20%3D%2014%5C%5C%5C%5CMultiply%20%5C%203%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C2x%20%3D%2014%20%5Ctimes%203%5C%5C%5C%5C2x%20%3D%2042%20%5C%5C%5C%5CDivide%5C%20both%5C%20sides%5C%20by%5C%202%5C%5C%5C%5Cx%20%3D%2042%2F2%5C%5C%5C%5Cx%20%3D%2021%5C%5C%5C%5CFor%20%5C%20x%20%3D%2021%5C%20the%20%5C%20given%20%5C%20equation%20%5C%20is%20%5C%20true.%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3><h3>Peace!</h3>