3 years ago

What is the density of a material, if 132 grams of the material occupies 3 cubic centimeters?

1 answer:

5 0

You need to divide here, so 132/3 = 44, so that means it's D, 44 g/cm3. Hope this helped! Brainliest is always appreciated.

You might be interested in

I don't understand my math class..and she left me with this problem. So how do I solve this?

Igoryamba

The triangle has to equal to 180. So add them up and equal it to 180

4 0

3 years ago

Amelia uses 66 patches of fabric per square foot to make a blanket. How many patches of fabric will she need to make a blanket t

poizon [28]

The answer is 10920. 720720/66=10920

3 0

3 years ago

How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?

MrRissso [65]

$\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3} \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(3x)^{3 \times \frac{5}{3} }}{(2y^3)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}$

Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

5 0

2 years ago

Can someone please help me?

shepuryov [24]

Answer:

Step-by-step explanation:

area = wl (6×4 = 24)

w width l length

4 0

1 year ago

Define the following term. greatest common factor

prohojiy [21]

A GCF ( Greatest Common Factor) is one factor that can be split evenly between the two numbers you have chosen.

For example, the greatest common factor of 4 and 8 would be 4 because this is the greatest number that can be split evenly with the numbers I have chosen.

I hope this helped.

5 0

2 years ago