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LenKa [72]
3 years ago
5

What is the density of a material, if 132 grams of the material occupies 3 cubic centimeters?

Mathematics
1 answer:
Andru [333]3 years ago
5 0
You need to divide here, so 132/3 = 44, so that means it's D, 44 g/cm3. Hope this helped! Brainliest is always appreciated.
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Need help asap the graphs below have the same shape. what is the equation of the red graph?
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The highlighted one is correct

B F(x) = 2 - x²

Step-by-step explanation:

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Convert each fraction to a decimal then a percent 4/25 3/11
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Answer:

4/25=0.16=16%

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Step-by-step explanation:

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3 years ago
A stunt man wants to drive a car off a ramp at an angle of 35∘ from the ground. He already has a ramp with an angle of 15∘. He p
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Answer:

The second ramp needs to have 25°.

Step-by-step explanation:

Required ramp angle for driving the car from the ground = 35°.

First ramp angle = 15°

Therefore, second ramp angle equals required ramp angle minus first ramp angle, which is = 35° - 15° = 20°

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4 0
3 years ago
Before every​ flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the ai
ollegr [7]

Answer:

The probability that the aircraft  is  overload = 0.9999

Yes , The pilot has to be take strict action .

Step-by-step explanation:

P.S - The exact question is -

Given - Before every​ flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 ​passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.

To find - What is the probability that the aircraft is​ overloaded ?

         Should the pilot take any action to correct for an overloaded aircraft ?

Proof -

Given that,

Mean, μ = 182.7

Standard Deviation, σ = 39.6

Now,

Let X be the Weight of the men

Now,

Probability that the aircraft is loaded be

P(X > 168 ) = P(\frac{x - \mu}{\sigma} > \frac{168 - \mu}{\sigma} )

                 = P( z > \frac{168 - 182.7}{39.6} )

                 = P( z > -0.371)

                 = 1 - P ( z ≤ -0.371 )

                 = 1 - P( z > 0.371)

                 = 1 - 0.00010363

                 = 0.9999

⇒P(X > 168) = 0.9999

As the probability of weight overload = 0.9999

So, The pilot has to be take strict action .

5 0
3 years ago
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