All categories

3 years ago

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

Mathematics

2 answers:

Alika [10]3 years ago

7 0

Answer:

Step-by-step explanation:

3x + y = 4

y = -3x + 4

y + 1 = -3(x - 7)

yuradex [85]3 years ago

4 0

Answer:

A) y + 1 = -3 ( x - 7 )

Step-by-step explanation:

I used the Desmos website. Hope this helps.

You might be interested in

Find the x and y intercepts of the graph of the equation y=x^2-5

mr_godi [17]

Answer:

x intercepts -sqrt(5), + sqrt(5)

y intercept -5

Step-by-step explanation:

y = x^2 -5

to find the x intercept set y=0 and solve for x

0 = x^2-5

add 5 to each side

5 = x^2

take the square root of each side

+- sqrt(5) = sqrt(x^2)

x = +-sqrt(5) there are 2 x intercepts since it is a quadratic

to find the y intercept set x=0 and solve for y

y = 0-5

y = -5

8 0

3 years ago

George has a small coin collection. He has collected 16 gold coins, 28 silver coins, 32 copper coins, and4 bronze coins. At a f

Neko [114]

He sold 12 coins, 16+28+32+4=80. 15% of 80 is 12

6 0

3 years ago

Read 2 more answers

Suppose the auction house from the preceding problem sold 200 tickets at $1 each, and had 16 prizes of $10 each. What is the new

Brilliant_brown [7]

200/160=1.25

200+160=360/1.25/160=200.8

so your answer is 0.8

4 0

3 years ago

How many yards will the players have run ?? Please help

Whitepunk [10]

Answer:

125.3 yards

Step-by-step explanation:

He wants them to run the so 110^2+60^2 =which is 125.3.

Hope this helps plz mark brainliest :D

8 0

3 years ago

The numbers on a football field indicate 10 yard increments. You walk around the perimeter of a football field between the pylon

Roman55 [17]

Answer:

5,333 square yards.

Step-by-step explanation:

Football fields have standard 100 yards length, if you walk the perimeter of a football field you will walk the twice the length and twice the width. Therefore, the width of the field can be found as follows:

$306.667 = 2L +2W\\W = \frac{306.667 - 2*100}{2} \\W= 53.33$

The area of the playing field is the product of the length by the width

$A = L*W\\A= 100*53.33\\A=5333$

The area of the playing field is 5,333 square yards.

5 0

3 years ago