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strojnjashka [21]
4 years ago
8

Please help me I need this question done by tonight. The amount that a consultant charges for her work can be modeled using a li

near function. For 4 hours of work, the consultant charges $400. For 5 hours of work, she charges $450. How much money does the consultant earn each hour?
Mathematics
1 answer:
nataly862011 [7]4 years ago
5 0

Answer: The consultant earn $50 each hour.

Explanation:

It is given that for 4 hours of work, the consultant charges $400. For 5 hours of work, she charges $450. The amount that a consultant charges for her work can be modeled using a linear function.

If the linear function represents the amount earn by consultant in hours the the coordinates can be written as (4, 400) and (5, 450).

If we want to find how much money does the consultant earn each hour, so first we have to find the slope of linear function which passing through two points (4, 400) and (5, 450).

\text{Slope}=\frac{y_2-y_1}{x_2-x_1}

\text{Slope}=\frac{450-400}{5-4}

\text{Slope}=\frac{50}{1}

\text{Slope}=50

In the linear function the slope show the earning of consultant per hour, therefore consultant earn $50 each hour.

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storchak [24]

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Work = e+24

F is not conservative.

Step-by-step explanation:

To find the work required to move an object in the force field  

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along the straight line from A(0,0,0) to B(-1,2,-5), we have to parameterize this segment.

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is a parameterization of the segment.

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\large W=\int_{C}Fdr

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\large \int_{C}Fdr =\int_{0}^{1}F(r(t))\circ r'(t)dt=\int_{0}^{1}F(-t,2t,-5t)\circ (-1,2,-5)dt=\\\\=\int_{0}^{1}(e^t,e^t,-5te^t)\circ (-1,2,-5)dt=\int_{0}^{1}(-e^t+2e^t+25te^t)dt=\\\\\int_{0}^{1}e^tdt-25\int_{0}^{1}te^tdt=(e-1)+25\int_{0}^{1}te^tdt

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I am assuming that we are finding 'x' when y = 9.

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