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2 years ago

1+1 abcdefghijklmnopqrstuvwxyandz

Mathematics

2 answers:

Cerrena [4.2K]2 years ago

6 0

Answer:

alk;hhhhhhsdfhdaglj;hldjghlja

Step-by-step explanation:

skad [1K]2 years ago

3 0

Answer:2

Step-by-step explanation: two 1 equal one 2

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I need to explain/show work. Help please

Fittoniya [83]

Answer:

adult tickets = 17, children tickets = 9

Step-by-step explanation:

Let x be the number of children and y the number of adults

Then given that 26 tickets are sold, we can write

x + y = 26 → (1)

Given that ticket cost was $194 we can write

5.5x + 8.5y = 194 → (2)

Rearrange (1) expressing y in terms of x by subtracting x from both sides

y = 26 - x → (3)

Substitute y = 26 - x into (2)

5.5x + 8.5(26 - x) = 194 ← distribute and simplify left side

5.5x + 221 - 8.5x = 194

- 3x + 221 = 194 ( subtract 221 from both sides )

- 3x = - 27 ( divide both sides by - 3 )

x = 9

Substitute x = 9 into (3) for corresponding value of y

y = 26 - 9 = 17

Hence number of adult tickets sold = 17

number of children tickets sold = 9

5 0

3 years ago

Find the slope A- 1/4 B- 1/3 C- 1/5 D- 2/3

soldi70 [24.7K]

Answer:

1/3

Step-by-step explanation:

if you move up 1 over three, the line intersects the graph

7 0

2 years ago

Read 2 more answers

jamal finished 5/6 of his homework .margaret finished 3/4 and steve finised 10/12 of his homeowrk. which 2 students finished the

Blababa [14]

Jamal and Steve finished the same amount of homework because 5/6 is the same as 10/12

7 0

3 years ago

The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,

Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

If the mean number of arrivals is 10

This means that $\mu = 10$

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347$

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is $P(X \leq 10)$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045$

$P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045$

$P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023$

$P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076$

$P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189$

$P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378$

$P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631$

$P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901$

$P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126$

$P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251$

$P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831$

58.31% probability that there are no more than 10 arrivals.

8 0

2 years ago

Find the missing value: x2 (squared) = 625 5 10 25 50

Alona [7]

$\bf x^2=625\implies x=\sqrt{625}\implies x=25$

5 0

3 years ago

Read 2 more answers