I'll give you a hint
20) Add 56 to both sides
23) Add 1.5 to both sides
Also, as a AP Calc BC student, laziness doesn't really help get a good job soo...
Answer:
y=2x+6
Step-by-step explanation:
Graph the coordinates
Go up to over one or down two left on
Get your y-intercept
put in y=mx+b
Answer:
1. Range is 37,IQR is 16.5, MAD is 9
2.Range is 35,IQR is 14, MAD is 8
3. Range is 76,IQR is 37, MAD is 19.1
4. Range is 8, IQR is 4, Mad is 20.4
5. Range is 62,IQR is16 , MAD is 13.08
6. Range is 42,IQR is 23,MAD is 12
Step-by-step explanation:
mrk me brainliest plz
So it is an isosceles triangle that means that the bottom two angles are equal...
so
40 = 5x
divide both sides by 5 and you get 8
now the triangle angles add up to 180
we make an equation out of it...
(2y + 20 ) + ( 5(8)) + 40 = 180
2y + 20 + 40 + 40 = 180
combine like terms
2y + 100 = 180
so subtract 100 from both sides
2y = 80
divide by 2 to isolate the variable
y = 40
You are correct!!! :)
The bigger engine is about 235.5 cubic centimeters larger than the smaller engine.
We need the answer in cubic centimeters. So let's convert 350 cubic inches to cubic centimeters. We will do it unit conversion way (the long way).
We will write cubic inches as three inches side-by-side
350 in^3
<h3>What is the ratio of the centimeter?</h3>
This way, we can multiply this by the ratio of centimeters to inches [2.54 cm = 1 inch], so that the units cancel and we have cubic centimeters (what we desire).
350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in
So, we can cancel the three inches top and bottom thus we have the answer in centimeters cubed. And the value is
350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in.
350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in=5735.47.
So 350 cubic inches is approximately 5735.5 cubic centimeters (rounded to 1 decimal place).
This is larger than a 5500 cubic centimeters engine.
5735.5-5500=235.5cubic centimeters.
The bigger engine is about 235.5 cubic centimeters larger than the smaller engine.
To learn more about the significant figures visit:
brainly.com/question/24491627
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