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shtirl [24]
3 years ago
15

Help me plz will mark brainliest

Mathematics
1 answer:
Ksju [112]3 years ago
7 0

Step-by-step explanation:

Given,

the bigger triangle (∆GFH), <HGF = 90° and <GFH = 60° and GF = 4

In the 30-60-90 triangle, FH = 4×2 = 8

or you can find it like this,

cos60 = 4/FH

FH = 4/cos60 = 8

Now, I is the midpoint of FH, so, FI = 8/2 = 4

now for ∆FGI,

<GFI = 60°, GF = 4, FI = 4, it's a equilateral triangle, so we can say GI = 4

Now we need to find the height of ∆FGI, for that,

area of ∆FGI = (√3/4)×4² = 4√3 = 6.92820323..

So height (GJ) = 2×area/side = 2×4√3/4 = 2√3 = 3.46410162.. [height of ∆GFI (Because altitude is perpendicular distance from a point) = GJ, given]

now, in ∆GJI, GJ = 2√3, GI = 4 and <GJI = 90° (since itsy altitude, the angle will be a right angle, i.e. 90°)

So, JI = √{4²-(2√3)²} = 2

Area = 2×2√3/2 = 2√3 = 3.46410162.. = 3.46 (rounded to the nearest hundredth)

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\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of 44c^5, 22c^3 , 11c^4

The greatest number that is a factor of two (or more) other numbers.

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\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}

First find the GCF of numbers and then find the GCF of variables and then multiply them together

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The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

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Then the greatest common factor is 11

\text{ Step 2: GCF of }c^5, c^3 , c^4

c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1

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