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3 years ago

Find the missing side lengths.

Mathematics

1 answer:

CaHeK987 [17]3 years ago

4 0

Use the Pythagorean theorem:

$x^2+8^2=17^2\\\\x^2+64=289\qquad\text{subtract 64 from both sides}\\\\x^2=225\to x=\sqrt{225}\\\\\boxed{x=15\ ft}$

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X = 7 + 3y

pogonyaev

<h3>Given Equation:</h3>

x = 7 + 3y

or, x - 3y - 7 = 0 ........ (i)

5x + 6y = 14

or, 5x + 6y - 14 = 0 .........(ii)

The value of x and y.

<h3>Solution:</h3>

By dividing eq. ii by 2, we get

5/2x + 3y - 7 = 0 ........ (iii)

By adding eq. i and eq. iii, we get

15/2x = 0

or, <u>x = 0</u> ........(iv)

By putting eq.(iv) in eq. (i), we get

0 - 3y - 7 = 0

or, -3y = 7

or, <u>y = </u><u>-</u><u>7/</u><u>3</u>

<h2>Answer: ( 0, -7/3 )</h2>

The value of x and y is 0 and -7/3 respectively.

5 0

3 years ago

Read 2 more answers

Which expressions are equivalent to z + (z + 6)

elixir [45]

Answer:

C 2(z+3)

Step-by-step explanation:

z+(z+6)

Combine like terms

2z+6

We can factor out a 2 from each term

2(z+3)

7 0

2 years ago

If 5 times a number increased by 30 is 15, what is the number?

weqwewe [10]

Answer:

let x=the number

5x+30=15

5x=15-30

5x=-15

5x/5=-15/5

x=-3

3 0

3 years ago

Read 2 more answers

4. Is it possible to have a triangle with the sides 6.1 cm, 3.2cm, 2.4cm? Justify your reason with suitable reason.

Dahasolnce [82]

Answer: No
Explanation: There is a rule that stays that a triangle's 2 least sides must add up to be greater than the biggest side. 3.2 plus 2.4 is not greater than 6.1.

3 0

2 years ago

What is 1/2(x+14) because i am having trouble solving it and no calculator has been able to help me also.

ivann1987 [24]

Hi there!

»»————-　★　————-««

I believe your answer is:

$\frac{1}{2}x+7$

»»————-　★　————-««

Here’s why:

⸻⸻⸻⸻

$\boxed{\text{Simplifying the equation...}}\\\\\frac{1}{2}(x+14)\\------------\\\rightarrow \frac{1}{2}*x = \frac{1}{2}x\\\\\rightarrow\frac{1}{2}*14=7\\\\\rightarrow \frac{1}{2}(x+14)= \boxed{\frac{1}{2}x+7}$

⸻⸻⸻⸻

»»————-　★　————-««

Hope this helps you. I apologize if it’s incorrect.

7 0

3 years ago