<h3>To find the product of 42.12 and 10^3, move the decimal point in 42.12 3 places to the right because 10^3 has 3 zeros</h3>
<em><u>Solution:</u></em>
Given that,

Which means,

Here, the exponent of 10 is positive ( which is 3)
When the exponent is positive, we have to move the decimal point to right
When you multiply a number by a power of 10, ( 10!, 10^2, and so on ) move the decimal point of the number to the right the same number of places as the number of zeros in the power of 10
Here, exponent is 3 , therefore move the decimal point right 3 places in 42.12
Therefore,

The first missing number in the sequence is 35, and the last missing number is 77.
<h3>Next number of the given sequence</h3>
The two missing numbers in the given sequence is calculated as follows;
= ? 49 63 ?
The given sequence is factor 7 which increases by 2
= 7 x 5 7 x 7 7 x 9 7 x 11
= 35 49 63 77
Thus, the first missing number in the sequence is 35, and the last missing number is 77.
Learn more about sequence here: brainly.com/question/6561461
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Answer:
-3.8
Step-by-step explanation:
u = 3.8
u × -1 = 3.8 × -1
-u = -3.8
Answer:
Seven crore eighty thousands sixty-seven.
Step-by-step explanation:
70080067
Seven crore eighty thousands sixty-seven.