See the attached figure which represent the rest of the question.
The rest of the question is the attached figure.
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As shown in the attached figure:
(1) ΔMNL is a right triangle at ∠MNL and ∠NML = 58°
∴ ∠L = 180° - (90°+58°) = 32°
(2) ΔQNL is a right triangle at ∠QNL and ∠QLN = 32°
∴ ∠Q = 180° - (90°+32°) = 58°
So, for both of ΔMNL and ΔQNL
1. ∠NLM = ∠ NLQ = 32°
2. ∠Q = ∠M = 58°
3. side NL = side NL
∴ ΔMNL is congruent to ΔQNL by AAS=======OR=======So, for both of ΔMNL and ΔQNL
1. ∠MNL = ∠QNL = 90°
2. side NL = side NL
3. ∠NLM = ∠ NLQ = 32°
∴ ΔMNL is congruent to ΔQNL by ASA=====================================
So, the correct answer is the first option
Yes, they are congruent by either ASA or AAS
Answer:
x =27
Step-by-step explanation:
from Z angls rule the agle (BDE) =72
and total angl on D =180
so, 2x +2x+72=180
4x = 180 -72
4x = 108 (divied both sides by 4)
x= 27
Answer:
x=6
UV=40
WV=40
UW=30
Step-by-step explanation:
GIVEN UV=WV
6X+4=40
X=6
NOW PUT X=6 in WV AND UW
8x-4=2x+35
8x-2x=35+4
6x=39
X=39/6
Answer:
-x - 3y + z
Step-by-step explanation:
Think of a imaginary 1(-1 because of the sign) in front of the parenthesis and distribute it to the other number and so x will become -x, 3y will become -3y and -z will become z because two negatives make a positive.