There are C(5,2) = 10 ways to choose 2 contraband shipments from the 5. There are C(11, 1) = 11 ways to choose a non-contraband shipment from the 11 that are not contraband. Hence there are 10*11 = 110 ways to choose 3 shipments that have 2 contraband shipments among them.
There are C(16,3) = 560 ways to choose 3 shipments from 16. The probability that 2 of those 3 will contain contraband is
110/560 = 11/56 ≈ 19.6%
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C(n,k) = n!/(k!(n-k)!)
Answer:
Correct expression: 85 + 0.06(t - 400)
Correct earnings: $91
Step-by-step explanation:
The expression Joan wrote is incorrect because instead, $85, she put $400 as her base salary. The correct expression would be 85 + 0.06(t - 400), where 85 is her base pay in dollars, and t - 400 represents her sales in dollars exceeding $400.
If Joan's sales were $500, she would not make $424.90, but
85 + 0.06(t - 400)
85 + 0.06(500 - 400)
85 + 0.06(100)
85 + 6
$91
Hope this helps.
Cheers,
Andy
Answer:
Using the Pythagorean Theorem:
distance^2 = 72^2 + 65^2
distance^2 = 5,184 + 4,225
distance^2 = 9,409
distance = 97 yards
"round-trip" distance = 97 * 2 = 194 yards
Step-by-step explanation:
To find this value, simply substitute the number 10 in for x in your equation:
The answer is 98.
Answer: c
Step-by-step explanation:
