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Gnesinka [82]
3 years ago
5

What mid ocean ridge cuts between South America and Africa

Physics
1 answer:
vazorg [7]3 years ago
5 0

Answer:

South Alantic

hope it helps.

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True or false nodes and antinodes occur in longitudinal waves
Vlad [161]
I believe it is false because longitudinal waves travel parallel to the vibration
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3 years ago
A steel ball is released just below the surface of thick oil in a cylinder.
Viefleur [7K]

Answer:

Increasing

Explanation:

I Hope it Helps

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3 years ago
When is it necessary to use relativistic quantum mechanics?
Ugo [173]

Answer:

To see objects smaller than microscopic limits

Explanation:

The theory of Relativistic Quantum mechanics can be applied to particles that are massive and propagates at all velocities even those which are comparable to the speed of light and is capable to accommodate particles that are mass less. This theory find its application in atomic physics, high energy physics, etc.

It is necessary to use relativistic quantum mechanics when it is desired to see the objects that are too small to be seen with the help of microscope.

4 0
3 years ago
What are the largest optical telescopes in use today? Why do astronomers want their telescopes to be as large as possible?
Simora [160]

The largest telescope currently used is the Gran Telescopio Canarias, (also known as GTC or GRANTECAN). It is 10.4m in diameter, slightly larger than the Keck telescopes in Hawaii.

The telescope observes the visible and infrared light coming from space and has a primary mirror of 10.4 meters, segmented into 36 hexagonal glass-ceramic pieces, 1.9 m between vertices, 8 cm thick, and 470 kg of mass each. The optical system is completed with two mirrors (secondary and tertiary) that form an image in seven focal stations.

Optically the diameter directly influences the magnification of the image. This added to the fact that astronomical objects are quite far away, a telescope of this magnitude allows to obtain more precise images of what is observed in space

6 0
4 years ago
An automobile whose speed is increasing at a rate of 0.800 m/s2 travels along a circular road of radius 10.0 m.
Ket [755]

(a) a_t = 0.800 m/s^2

The tangential acceleration component of the car is simply equal to the change of the tangential speed divided by the time taken:

a_t = \frac{\Delta v}{\Delta t}

This rate of change is already given by the problem, 0.800 m/s^2, so the tangential acceleration of the car is

a_t = 0.800 m/s^2

(b) a_c = 0.9 m/s^2

The centripetal acceleration component is given by

a_c = \frac{v^2}{r}

where

v is the tangential speed

r is the radius of the trajectory

When the speed is v = 3.00 m/s, the centripetal acceleration is (the radius is r = 10.0 m):

a_c = \frac{(3.00 m/s)^2}{10.0 m}=0.9 m/s^2

(c) 1.2 m/s^2, 48.4^{\circ}

The centripetal acceleration and the tangential acceleration are perpendicular to each other, so the magnitude of the total acceleration can be found by using Pythagorean's theorem:

a=\sqrt{a_t^2+a_c^2}=\sqrt{(0.8 m/s^2)^2+(0.9 m/s^2)^2}=1.2 m/s^2

and the direction is given by:

tan \theta =\frac{a_c}{a_t}=\frac{0.9 m/s^2}{0.8 m/s^2}=1.125\\\theta=tan^{-1}(1.125)=48.4^{\circ}

where the angle is measured with respect to the direction of the tangential acceleration.

4 0
3 years ago
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