A steel ball is released just below the surface of thick oil in a cylinder.
1 answer:
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Answer:
(a). The amplitude of the motion is 0.926 m.
(b). The block’s maximum acceleration is 182.31 m/s².
(c). The maximum force the spring exerts on the block is 291.69 N.
Explanation:
Given that,
Mass of block =1.60 kg
Force constant = 315 N/m
Speed = 13.0 m/s
(a). We need to calculate the amplitude of the motion
Using conservation of energy
Put the value into the relation
(b). We need to calculate the block’s maximum acceleration
Using formula of acceleration
Put the value into the formula
(c). We need to calculate the maximum force the spring exerts on the block
Using formula of force
Put the value into the formula
Hence, (a). The amplitude of the motion is 0.926 m.
(b). The block’s maximum acceleration is 182.31 m/s².
(c). The maximum force the spring exerts on the block is 291.69 N.