Point E is on line segment DF. Given DE
EF.
6 and DF =9, determine the length EF
1 answer:
Answer:
<h2>3</h2>
Step-by-step explanation:
IF point E lies on the line segment DF, this means that all the points DEF are collinear and DE+EF = DF.
Given parameter
DE = 6
DF = 9
Required
EF
Substituting the given parameter into the expression above to get the required will be;
DE+EF = DF.
EF = DF-DE
EF = 9-6
EF = 3
Hence the length of EF is equivalent to 3
You might be interested in
Answer:
Step-by-step explanation:
B. x4 + 4x3 + x2 + 4x
Answer:
11:15
Step-by-step explanation:
Answer:
incompleted question
Step-by-step explanation:
......?
Answer:
red pencil=5/24
yellow pencil=6/24
Blue pencil=8/24
Orange pencil=3/24
purple pencil=2/24
You divide 91/14 to get w=6.5.
