Point E is on line segment DF. Given DE
EF.
6 and DF =9, determine the length EF
1 answer:
Answer:
<h2>3</h2>
Step-by-step explanation:
IF point E lies on the line segment DF, this means that all the points DEF are collinear and DE+EF = DF.
Given parameter
DE = 6
DF = 9
Required
EF
Substituting the given parameter into the expression above to get the required will be;
DE+EF = DF.
EF = DF-DE
EF = 9-6
EF = 3
Hence the length of EF is equivalent to 3
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Step-by-step explanation:
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336 votes total.
Answer:
1.76
Step-by-step explanation:
3.9-7.4x=-4.5x+9
-2.9x=5.1
x=1.758 or 1.76
I hope this helps, if not i'm sorry.
