Three coins are tossed onto a table and the numbers of heads is recorded. The number of possible outcomes for this event is
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Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Substitute , so that
. Then the ODE is equivalent to
which is separable as
Split the left side into partial fractions,
so that integrating both sides is trivial and we get
Given the initial condition , we find
so that the ODE has the particular solution,
Answer:
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