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zheka24 [161]
3 years ago
9

Can you solve for x for this shape?

Mathematics
2 answers:
mr Goodwill [35]3 years ago
8 0
An exterior angle of a triangle is equal to the sum of the two angles opposite to it. So we have:

\sf 6x+1+20=9x-6

Now just solve for 'x'. First, simplify:

\sf 6x+21=9x-6

Add 6 to both sides:

\sf 6x+27=9x

Subtract 6x to both sides:

\sf 27=3x

Divide 3 to both sides:

\boxed{\sf x=9}
Ilia_Sergeevich [38]3 years ago
5 0
Hi my friend
6x + 1 + 20 = 9x - 6 (exterior angle of triangle)
3x = 27
x = 9
hope it helps☺
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A rectangular sheet of steel is being cut so that the length is four times the width. The perimeter of the sheet must be less th
Karolina [17]

Answer:

\frac{5}{2} l

Step-by-step explanation:

6 0
4 years ago
(8.11×107)–(4.3×107)
Ivanshal [37]

Answer: 407.67

Explanation:

(8.11×107)–(4.3×107) =

(8.11)(107)−(4.3)(107) =

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5 0
3 years ago
What the second answer ​
Debora [2.8K]

Answer:

1. y' = 3x² / 4y²

2. y'' = 3x/8y⁵[(4y³ – 3x³)]

Step-by-step explanation:

From the question given above, the following data were obtained:

3x³ – 4y³ = 4

y' =?

y'' =?

1. Determination of y'

To obtain y', we simply defferentiate the expression ones. This can be obtained as follow:

3x³ – 4y³ = 4

Differentiate

9x² – 12y²dy/dx = 0

Rearrange

12y²dy/dx = 9x²

Divide both side by 12y²

dy/dx = 9x² / 12y²

dy/dx = 3x² / 4y²

y' = 3x² / 4y²

2. Determination of y''

To obtain y'', we simply defferentiate above expression i.e y' = 3x² / 4y². This can be obtained as follow:

3x² / 4y²

Let:

u = 3x²

v = 4y²

Find u' and v'

u' = 6x

v' = 8ydy/dx

Applying quotient rule

y'' = [vu' – uv'] / v²

y'' = [4y²(6x) – 3x²(8ydy/dx)] / (4y²)²

y'' = [24xy² – 24x²ydy/dx] / 16y⁴

Recall:

dy/dx = 3x² / 4y²

y'' = [24xy² – 24x²y (3x² / 4y² )] / 16y⁴

y'' = [24xy² – 18x⁴/y] / 16y⁴

y'' = 1/16y⁴[24xy² – 18x⁴/y]

y'' = 1/16y⁴[(24xy³ – 18x⁴)/y]

y'' = 1/16y⁵[(24xy³ – 18x⁴)]

y'' = 6x/16y⁵[(4y³ – 3x³)]

y'' = 3x/8y⁵[(4y³ – 3x³)]

6 0
3 years ago
Please Help ASAP Anyone please help me answer these questions
N76 [4]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Match each complex number with its equivalent expression i^157 i^315 i^102 i^76
ryzh [129]

Answers:

i^{157} = i\\\\i^{315} = -i\\\\i^{102} = -1\\\\i^{76} = 1\\\\

=====================================================

Explanation:

By definition, i = \sqrt{-1}

Squaring both sides gets us i^2 = -1

Then multiply both sides by i to get i^3 = -i

Repeat the last step and you should get i^4 = -i^2 = -(-1) = 1

---------------

Notice we have this pattern going on:

i^0 = 1\\\\i^1 = i\\\\i^2 = -1\\\\i^3 = -i\\\\i^4 = 1\\\\

Once we reach i^4, we start the process over again.

It repeats every 4 terms.

This means we'll divide the exponent over 4 and look at the remainder. We ignore the quotient completely.

157/4 = 39 remainder 1

That remainder 1 is the exponent of the simplified term

i^{157} = i^1 = i

---------------

Similarly,

315/4 = 78 remainder 3

So i^{315} = i^3 = -i

---------------

102/4 = 25 remainder 2

i^{102} = i^2 = -1

----------------

76/4 = 19 remainder 0

i^{76} = i^0 = 1

8 0
2 years ago
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