Answer:
Let's see what to do buddy...
Step-by-step explanation:

And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
By first principles, the derivative is

Use the binomial theorem to expand the numerator:


where

The first term is eliminated, and the limit is

A power of
in every term of the numerator cancels with
in the denominator:

Finally, each term containing
approaches 0 as
, and the derivative is

It would help you to make a table because say your answer is 8 pieces is 1 minute and then the next question is how long wouls it take sam to cut 24 pieces you would use the table with you first answer and then multiple both numbers 3 times to give you your answer. Its really just a way to have more organized answers