MN is the mid-line of a trapezoid HJLK.<span>
The length of the mid-line of a trapezoid is half of the sum of the lengths of its bases </span>⇒
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(KL + HJ)/2 = MN
(KL + 45)/2 = 28
KL + 45 = 28 * 2
KL + 45 = 56
KL = 56 - 45
KL = 11
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The plc as value of 6 in12.6 is the tenths place
2 , -5 , 1
those are the coefficients (C)
We're going to use the equation given but let's first make sure we understand what the equation IS saying:
Area of a kite= [(1st diagonal) × (2nd diagonal)]/2
Now, let's find the 2 diagonals. In the case of kite shapes one of the diagonals is the line that goes from W to Y and the other is the line going from X to Z. In a kite they will always cross (no matter their lengths).
Now that we know the diagonals we can add the lengths that are given for each line to know what to multiply.
Line W to Y: 20+12= 32
Line X to Z: 12+12= 24
Now let's plug these numbers into the equation (it doesn't matter the order of the diagonals because we're just gonna be multiplying them either way!)
So...
(32×24)/2= 384 units squared (because it is area)
Step-by-step explanation:
Option B. Here Adam Ct. is perpendicular to Betha Dr. and Charles. So, St. Bertha Dr. || Charles St. Since they are parallel to each other
