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Rufina [12.5K]
3 years ago
9

USING STRUCTURE What type of pair of angles are 6 and 13?

Mathematics
1 answer:
ziro4ka [17]3 years ago
8 0

Answer:

Consecutive interior angles

Step-by-step explanation:

This chart may also help

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G(t) = 2t - 5; Find g(-9)
zaharov [31]

Answer:

g = -23

Step-by-step explanation:

5 0
3 years ago
Jane has 6/7 of a yard of ribbon. She uses 3/4 of a yard to trim an ornament. how much ribbon is left?
Degger [83]

Answer:

2/28

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Please help me with this question
Tanya [424]
Your answer would be -16.
7 0
3 years ago
Very easy math question
charle [14.2K]

Answer:

C. 179 ft²

Step-by-step explanation:

Area of circular path or walkway

= π × (R + r) × width

Where

R= Outer radius

r = Inner Radius

Diameter = 16 feet

Width = 3 feet

Inner Radius = Diameter/2

= 16 feet/2 = 8 feet

Outer Radius = 8 + 3 = 11 ft

Hence:

= π × (11 + 8) × 3

= π × 19 × 3

= 179.07078125 ft²

Approximately = 179 ft²

The area of the circular walkway = 179ft²

Option C is correct.

7 0
3 years ago
g Suppose a factory production line uses 3 machines, A, B, and C for making bolts. The total output from the line is distributed
Vladimir [108]

Answer:

The probability that it came from A, given that is defective is 0.362.

Step-by-step explanation:

Define the events:

A: The element comes from A.

B: The element comes from B.

C: The element comes from C.

D: The elemens is defective.

We are given that P(A) = 0.25, P(B) = 0.35, P(C) = 0.4. Recall that since the element comes from only one of the machines, if an element is defective, it comes either from A, B or C. Using the probability axioms, we can calculate that

P(D) = P(A\cap D) + P(B\cap D) + P(C\cap D)

Recall that given events E,F the conditional probability of E given F is defined as

P(E|F) = \frac{P(E\cap F)}{P(F)}, from where we deduce that

P(E\cap F) = P(E|F)P(F).

We are given that given that the element is from A, the probability of being defective is 5%. That is P(D|A) =0.05. Using the previous analysis we get that

P(D) = P(A)P(D|A)+P(B) P(D|B) + P(C)P(D|C) = 0.05\cdot 0.25+0.04\cdot 0.35+0.02\cdot 0.4 = 0.0345

We are told to calculate P(A|D), then using the formulas we have

P(A|D) = \frac{P(A\cap D)}{P(D)}= \frac{P(D|A)P(A)}{P(D)}= \frac{0.05\cdot 0.25}{0.0345}= 0.36231884

3 0
3 years ago
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