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1 year ago

6

The cubic curve y = x'3 + ax'2 + bx + c passes through the point (1,3) and has tangent line y = x - 2 at the point (0,-2). What

are the values of a, b, and c?

1 answer:

xz_007 [3.2K]1 year ago

6 0

Answer:

answer to your question is: a = 3, b = 1, c = -2

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