The cubic curve y = x'3 + ax'2 + bx + c passes through the point (1,3) and has tangent line y = x - 2 at the point (0,-2). What
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Answer: The expression given simplifies to: 3 .
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Explanation:
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Given: (3x - 6) / (x-2) ;
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Factor the numerator into: 3(x-2).
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Now, rewrite the expression as:
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;
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The "(x - 2)" values cancel to "1" ; since "(x - 2) ÷ (x - 2) = 1" ;
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and we are left with: "3 ".
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_________________________________________________
Explanation:
________________________________________________
Given: (3x - 6) / (x-2) ;
___________________________
Factor the numerator into: 3(x-2).
________________________________
Now, rewrite the expression as:
____________________________
________________________________________
The "(x - 2)" values cancel to "1" ; since "(x - 2) ÷ (x - 2) = 1" ;
_______________________________________________________
and we are left with: "3 ".
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