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rodikova [14]
3 years ago
8

If the lowest temperature in Whitesboro for the week was -1°F and the highest temperature was 20°F, what was the total change in

temperature?
Will give brainliest!!
Mathematics
2 answers:
Fittoniya [83]3 years ago
6 0

Answer:

21°F

Step-by-step explanation:

It went from -1 to 20

[-1]= 1

1+20

21

it went up or down 21°F

      A        A

     (๑٥〰️٥๑)️                      

ϞϞノ  --  -- 乀  •⃠  

Talja [164]3 years ago
3 0
Answer: The total change is 21.

Since you want to find the change from the lowest to highest, make it into a subtraction problem. First of all, take the smallest number in front of the largest.

20 -1

Next, add a minus sign in between, your equation should look like this:

20 - (-1) = x

Then, you cancel out the negative signs. After that you solve it

20 - (-1) -> 20 + 1.

Lastly, you add them together.

20 + 1 = 21.

In conclusion, the answer is 21.

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Find the value of y.
olga nikolaevna [1]
Try this option:
1. the sides of the biggest triangle are 16; x and √(16²-x²); the sides of the smallest triange are x;5 and y. The smallest triangle ~ the biggest triangle. Using the property of the similar triangles: 
\frac{x}{5} = \frac{16}{x}, \ then \ x= \sqrt{80}
2. according to the Pyphagorean theorem (in the smallest triangle):
y= \sqrt{ \sqrt{80^2} -5^2} = \sqrt{55}

answer: y=√55.
4 0
3 years ago
While driving home from work Donald's windshield got cracked by a small rock, causing $500 worth of damage. Given the policy sum
Dafna11 [192]

I think you would most likely add all of them well I think

4 0
2 years ago
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Prove that if {x1x2.......xk}isany
Radda [10]

Answer:

See the proof below.

Step-by-step explanation:

What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where n\geq 2. If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"

Proof

Since we have a if and only if w need to proof the statement on the two possible ways.

If X is linearly dependent, then a vector is a linear combination

We suppose the set X= (x_1, x_2,....,x_n) is linearly dependent, so then by definition we have scalars c_1,c_2,....,c_n in C such that:

c_1 x_1 +c_2 x_2 +.....+c_n x_n =0

And not all the scalars c_1,c_2,....,c_n are equal to 0.

Since at least one constant is non zero we can assume for example that c_1 \neq 0, and we have this:

c_1 v_1 = -c_2 v_2 -c_3 v_3 -.... -c_n v_n

We can divide by c1 since we assume that c_1 \neq 0 and we have this:

v_1= -\frac{c_2}{c_1} v_2 -\frac{c_3}{c_1} v_3 - .....- \frac{c_n}{c_1} v_n

And as we can see the vector v_1 can be written a a linear combination of the remaining vectors v_2,v_3,...,v_n. We select v1 but we can select any vector and we get the same result.

If a vector is a linear combination, then X is linearly dependent

We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select v_1 and we have this:

v_1 = c_2 v_2 + c_3 v_3 +...+c_n v_n

For scalars defined c_2,c_3,...,c_n in C. So then we have this:

v_1 -c_2 v_2 -c_3 v_3 - ....-c_n v_n =0

So then we can conclude that the set X is linearly dependent.

And that complet the proof for this case.

5 0
3 years ago
How can you decompose the composite figure to determine its area?
laiz [17]

see the attached figure to better understand the problem

we know that

The Area of the composite figure is equal to the sum of Area 1, Area 2 and Area 3

The Area 1 is a triangle

The Area 2 is a rectangle

The Area 3 is equal a semicircle

therefore

<u>the answer is the option</u>

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6 0
3 years ago
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The graph of ƒ(x) = -√x is shifted to the right five units. The domain of the function represented by this graph is x ≥&gt;≤&lt;
Mars2501 [29]

Answer:

Domain = [5,∞)

Step-by-step explanation:

Given: f(x)=-\sqrt{x}

We are given that f(x) is shifted right by 5 units.

Rule : f(x)→f(x-b)

The graph f(x) shifted b units right

So, using rule : -\sqrt{x} →   -\sqrt{x-5}

So, g(x)=-\sqrt{x-5}

Now to find domain:

x-5>0

x>5

So, Domain = [5,∞).

8 0
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