B by making the solute particles smaller because it decrease the dissolving time.
like an example about tea and sugar when you stir the tea it allows the sugar to dissolve faster
Answer:
The solubility product of calcium hydroxide is
.
Explanation:
To calculate the concentration of acid, we use the equation given y neutralization reaction:
![n_1M_1V_1=n_2M_2V_2](https://tex.z-dn.net/?f=n_1M_1V_1%3Dn_2M_2V_2)
where,
are the n-factor, molarity and volume of acid which is ![HCl](https://tex.z-dn.net/?f=HCl)
are the n-factor, molarity and volume of base which is
.
We are given:
![n_1=1\\M_1=?0.0983 M\\V_1=11.21 mL\\n_2=2\\M_2=?\\V_2=50.00 mL](https://tex.z-dn.net/?f=n_1%3D1%5C%5CM_1%3D%3F0.0983%20M%5C%5CV_1%3D11.21%20mL%5C%5Cn_2%3D2%5C%5CM_2%3D%3F%5C%5CV_2%3D50.00%20mL)
Putting values in above equation, we get:
![1\times 0.0983 M\times 11.21 mL=2\times M_2\times 50.00 mL\\\\M_2=0.01102 M](https://tex.z-dn.net/?f=1%5Ctimes%200.0983%20M%5Ctimes%2011.21%20mL%3D2%5Ctimes%20M_2%5Ctimes%2050.00%20mL%5C%5C%5C%5CM_2%3D0.01102%20M)
Molarity of calcium hydroxide solution = 0.01102 M
![Ca(OH)_2\rightleftharpoons Ca^{2+}(aq)+2OH^-(aq)](https://tex.z-dn.net/?f=Ca%28OH%29_2%5Crightleftharpoons%20Ca%5E%7B2%2B%7D%28aq%29%2B2OH%5E-%28aq%29)
1 mole of calcium hydroxide gives 1 mole of calcium ions and 2 moles of hydroxide ions.
![[Ca^{2+}]=1\times 0.01102 M=0.01102 M](https://tex.z-dn.net/?f=%5BCa%5E%7B2%2B%7D%5D%3D1%5Ctimes%200.01102%20M%3D0.01102%20M)
![[OH^{-}]=2\times 0.01102 M=0.02204 M](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%3D2%5Ctimes%200.01102%20M%3D0.02204%20M)
Solubility product is given by:
![K_{sp}=[Ca^{2+}][OH^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCa%5E%7B2%2B%7D%5D%5BOH%5E-%5D%5E2)
![=0.01102 M\times (0.02204 M)^2=5.35\times 10^{-6}](https://tex.z-dn.net/?f=%3D0.01102%20M%5Ctimes%20%280.02204%20M%29%5E2%3D5.35%5Ctimes%2010%5E%7B-6%7D)
The solubility product of calcium hydroxide is
.
D. Marble caused by heat and lots of pressure.
Answer:
12.1; acidic
Explanation:
I'm assuming the hydrogen concentration is H+.
So, first we must find pH.
pH = -log[H+]
I simply just plugged in the concentration.
I get 1.9 as the pH. This means that the substance is very acidic since it has a low pH.
Now to find poH.
poH + pH = 14
I simply plugged in once again!
I get 12.1 as the poH. This also determines that the substance is very acidic since it has a high poH.
Answer:
ummmmmmmmmm awwwwwwww u don't need anyone if that's what u mean
us single pringles need to stick together