Explanation:
Relation between pressure of water and its droplet is as follows.
where, p = pressure of droplet
= water pressure in given temperature
= 
M = Molecular Weight in Kg/Mol (0.018 for water)
r = radius in meters
= density of water in 
(1000 
)
R = ideal gas constant (8.31)
T = temperature in Kelvin
(a)
We will calculate the value of p as follows.
p = 
= 
= 26.8 torr
(b) And, vapor pressure of spherical water droplets of radius 2.0 
or 
p =
= 
= 25.2 torr
The answer is D) 144 grams O2
The empirical formula is C₂H₆O.
We must calculate the <em>masses of C, H, and O</em> from the masses given.
<em>Mass of C</em> =38.20 g CO₂ × (12.01 g C/44.01 g CO₂) = 10.424 g C
<em>Mass of H</em> = 23.48 g H₂O × (2.016 g H/18.02 g H₂O) = 2.6268 g H
<em>Mass of O</em> = Mass of compound - Mass of C - Mass of H
= (20.00 – 10.424 – 2.6268) g = 6.9487 g
Now, we must <em>convert these masses to moles</em> and <em>find their ratios</em>.
From here on, I like to summarize the calculations in a table.
<u>Element</u> <u>Mass/g</u> <u>Moles</u> <u>Ratio</u> <u>Integers</u>
C 10.424 0.8680 1.999 2
H 2.6268 2.606 6.001 6
O 6.9487 0.4343 1 1
The empirical formula is C₂H₆O.
Low air pressure cause it was on my test last year
Answer:
The correct answer is : The particles within all three states of matter are constantly moving.
Explanation:
The particles in the solid, liquid and gaseous states are in motion. In the latter is where they present greater movement and high kinetic energy, then follow the liquid state and finally the solid where the movement is more restricted (in this case, the particles vibrate).
