Answer : The heat required is, 7200 calories.
Explanation :
The process involved in this problem are :
The expression used will be:
where,
m = mass of ice = 10.0 g
= specific heat of liquid water =
= enthalpy change for fusion =
= enthalpy change for vaporization =
Now put all the given values in the above expression, we get:
Therefore, the heat required is, 7200 calories.