Answer:
269.068 kJ/mol.
Explanation:
<em>ln (k₂/k₁) = (Eₐ/R) [(T₂ - T₁)/(T₁T₂)].</em>
<em>k₁ = 6.20 x 10⁻⁴ min⁻¹, T₁ = 700.0 K.</em>
<u><em>To get k₂:</em></u>
in first order reactions: k = 0.693/(half-life).
∴ k₂ = 0.693/(29.0 min) = 2.39 x 10⁻² min⁻¹, T₂ = 760.0 K.
∵ ln (k₂/k₁) = (Eₐ/R) [(T₂ - T₁)/(T₁T₂)]
∴ ln [(2.39 x 10⁻² min⁻¹)/(6.20 x 10⁻⁴ min⁻¹)] = (Eₐ/(8.314 J/mol.K)) [(760.0 K - 700.0 K) / (760.0 K)(700.0 K)].
3.65 = (Eₐ/(8.314 J/mol.K)) (1.128 x 10⁻⁴).
<em>∴ Eₐ =</em> (3.65)(8.314 J/mol.K) / (1.128 x 10⁻⁴) = <em>269.068 kJ/mol.</em>
Answer:
Explanation:
From the given information;
Let Q(t) = mass of dye in the tank as a function of time
The mass in the tank = 200 L × (1g/L) = 200 g
Using the law of mass conservation;
Q(0) = 200
By finding the solution to the ODE using the method of separation of variables;
Using the initial condition;
200 = Q(0) = C
1% of 200g = 2g of dye solution
∴
t = 460.5 hours
MAGNESIUM(Mg) posses the up mentioned electronic configuration
Answer:
<em>Heat</em>
Explanation: When matter is heated enough, the molecules move faster and with greater energy. If enough heat is added, a solid can become liquid and a liquid can become gas. In the same way, molecules slow down when they are cooled.
Answer:
Flourine
Explanation:
Oxidation number will be +1 for oxygen and -1 for Flourine