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max2010maxim [7]
3 years ago
15

Find the area and round to the nearest hundredth

Mathematics
1 answer:
yanalaym [24]3 years ago
7 0

Answer:

3.14

Step-by-step explanation:

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Please Help me ASAP read the problem below
SashulF [63]

PART 1: Find the surface area of each section.

The formula for finding the area of a triangle is A = 1/2(b)(h); where b = base length and h = height. And the formula for finding the area of a rectangle is A = (l)(w); where l = length and w = width.

I'll start with the gold triangles, which are both the same size so I only need to calculate once.

A = 1/2(b)(h)

A = 1/2(7)(8.6)

A = 1/2(60.2)

A = 30.1 cm²

Now, I'll find the area of the blue triangles.

A = 1/2(b)(h)

A = 1/2(12)(7)

A = 1/2(84)

A = 42 cm²

Now, I'll find the area of the rectangular base.

A = (l)(w)

A = (12)(7)

A = 84 cm²

PART 2: Find the amount of foil in each color needed to cover 1 ornament.

There are two gold triangles, so all we have to do is multiply the area of the gold triangle by 2.

(30.1)(2) = 60.2 cm²

There are two blue triangles, so all we have to do it multiply the area of the blue triangle by 2.

(42)(2) = 84 cm²

And Olga will need 84 cm² of black foil to cover the rectangular base.

PART 3: Find the total amount of foil needed to cover 1 ornament and then 100 ornaments.

To find the total amount of foil needed, just add the amounts found in the previous step.

60.2 + 84 + 84 = 228.2 cm²

Olga will need 228.2 cm² of foil to cover 1 ornament.

(228.2)(100) = 22820 cm²

Olga will need 22, 820 cm² of foil to cover 100 ornaments.

PART 4: Fill in the blanks to give your answer.

Surface area of black face(s) = 84 cm²

Surface area of blue face(s) = 84 cm²

Surface area of gold face(s) = 60.2 cm²

Total surface area of 1 ornament = 228.2 cm²

Total surface area of 100 ornaments = 22, 820 cm²

Hope this helps!

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Find - square root 36<br> A.+6<br> B.-6<br> C.6<br> D.18<br> Help the I
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Answer:

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Step-by-step explanation:

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<span>3 x (6 x 7 – 2.5 x 4)
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=96
answer<span> D) 96</span>
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He value of variable for which the polynomial becomes zero is called as the zeroes of the polynomial. For Example: Consider p(x)
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OK this is hard math

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All investments carry the same amount of risk?
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Im not sure what you are trying to ask but any investment can be risky, yes.
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