All categories

3 years ago

how do you convert F=1.8c+32 temperature I'm degrees Celsius c to a temperature in degrees Fahrenheit f

Mathematics

1 answer:

irakobra [83]3 years ago

4 0

Answer:

Step-by-step explanation:

F=1.8C+32 is the formula needed to convert a temperature in degrees C to the equivalent temperature in degrees F. Use it.

Example: Suppose that C = 27. What would the equivalent temperature in degrees F be?

Substitute 27 for C in F=1.8C+32. We get F=1.8(27)+32 80.6 degrees F.

Answer: 27 degrees C is equivalent to 80.6 degrees F.

You might be interested in

8x^2+32x-96<img src="https://tex.z-dn.net/?f=8x%5E%7B2%7D%20%2B36x-96" id="TexFormula1" title="8x^{2} +36x-96" alt="8x^{2} +36x-

erma4kov [3.2K]

Answer:

−19282+104−96

Step-by-step explanation:

hopefully this helps, I'm not sure I'd it is correct though

4 0

3 years ago

Darren invests $4,500 into an account that earns 5% annual interests. How much will be in the account after 10 years if the inte

Tom [10]

We have been given that Darren invests $4,500 into an account that earns 5% annual interests. We are asked to find the amount in his account after 10 years, if the interest rate is compounded annually, quarterly, monthly, or daily.

We will use compound interest formula to solve our given problem.

$A=P(1+\frac{r}{n})^{nt}$ , where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

$5\%=\frac{5}{100}=0.05$

When compounded annually, $n=1$ :

$A=4500(1+\frac{0.05}{1})^{1\cdot 10}$

$A=4500(1.05)^{10}$

$A=4500(1.6288946267774414)$

$A=7330.025820498\approx 7330.03$

When compounded quarterly, $n=4$ :

$A=4500(1+\frac{0.05}{4})^{4\cdot 10}$

$A=4500(1.0125)^{40}$

$A=4500(1.6436194634870132)$

$A=7396.28758569\approx 7396.29$

When compounded monthly, $n=12$ :

$A=4500(1+\frac{0.05}{12})^{12\cdot 10}$

$A=4500(1.00416666)^{120}$

$A=4500(1.64700949769)$

$A=7411.542739605\approx 7411.54$

When compounded daily, $n=365$ :

$A=4500(1+\frac{0.05}{365})^{365\cdot 10}$

$A=4500(1.0001369863013699)^{3650}$

$A=4500(1.6486648137656943695)$

$A=7418.9916619456\approx 7419.00$

Since amount earned will be maximum, when interest is compounded daily, therefore, Darren should use compounded daily interest rate.

3 0

3 years ago

What do tge coefficents on the second and first degree terms in the original equation tell you about the arrows flight

kati45 [8]

-4:9 - This is half of the local gravitational constant, -9.8 m/s^2.

29:4 - The initial velocity of the arrow as it was shot upward was 29.4 m/s <u>(approximately 66 mph)</u>

6 0

3 years ago

Please help (10 points) asap

slava [35]

Answer:

A) 60 Miles per gallon

B) 10 Mins per mile

C) $0.45 per ounce

4 0

4 years ago

Please write a equation for this table

Hitman42 [59]

Answer:

y = 5x +2

Step-by-step explanation:

The point (0, 2) tells us the y-intercept is 2.

If we translate the table down 2 units by subtracting 2 from every y-value, it becomes ...

6, 30

-2, -10

0, 0

10, 50

We notice these values are all related by a factor of 5 (they are proportional). That means the equation will be a straight line with slope 5 and y-intercept 2.

y = 5x +2

6 0

2 years ago

how do you convert F=1.8c+32 temperature I'm degrees Celsius c to a temperature in degrees Fahrenheit f​

how do you convert F=1.8c+32 temperature I'm degrees Celsius c to a temperature in degrees Fahrenheit f